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ANEK [815]
3 years ago
14

What is 9 and 1/2 + 12 and 11/20

Mathematics
2 answers:
irina [24]3 years ago
8 0
9\left(\frac{1}{2}\right)+12\left(\frac{11}{20}\right) \ \textgreater \  \mathrm{Remove\:parentheses}:\ \left(a\right)=a \ \textgreater \  9\cdot \frac{1}{2}+12\cdot \frac{11}{20}

9\cdot \frac{1}{2} \ \textgreater \  \mathrm{Multiply\:fractions}:\ \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c}\ \textgreater \  \frac{1\cdot \:9}{2} \ \textgreater \  \mathrm{Apply\:rule}\:1\cdot \:a=a
\frac{9}{2}

2\cdot \frac{11}{20} \ \textgreater \  \mathrm{Multiply\:fractions}:\ \:a\cdot \frac{b}{c}=\frac{a\:\cdot \:b}{c} \ \textgreater \  \frac{11\cdot \:12}{20}

\mathrm{Multiply\:the\:numbers:}\:11\cdot \:12=132 \ \textgreater \  \frac{132}{20}

\mathrm{Cancel\:the\:common\:factor:}\:4 \ \textgreater \  \frac{33}{5} \ \textgreater \  \frac{9}{2}+\frac{33}{5}

Now we want to find the LCD which is least common denominator.
\mathrm{Find\:the\:least\:common\:denominator\:}2\cdot \:5=10 \ \textgreater \  10

\mathrm{Adjust\:Fractions\:based\:on\:the\:LCD} \ \textgreater \  \frac{9\cdot \:5}{10}+\frac{33\cdot \:2}{10}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\ \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

\frac{5\cdot \:9+2\cdot \:33}{10} \ \textgreater \  5\cdot \:9+2\cdot \:33 \ \textgreater \  \mathrm{Multiply\:the\:numbers:}\:5\cdot \:9=45

45+2\cdot \:33 \ \textgreater \  \mathrm{Multiply\:the\:numbers:}\:2\cdot \:33=66 \ \textgreater \  45+66 \ \textgreater \  111

Therefore\;\frac{111}{10}\;is\;our\;answer!

Also the decimal is 11.1.

Hope this helps!
tiny-mole [99]3 years ago
5 0
22.05 as a decimal and 22 1/20 as a fraction
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Two mechanics worked on a car. The first mechanic worked for 20 hours, and the second mechanic worked for 15 hours. Together the
klasskru [66]

The rate charged per hour by each mechanic was:  x = 75 $ / hr and y = 115 $ / hr.

<h3>What is a system of equations?</h3>

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Given;

The first mechanic worked for 20 hours, and the second mechanic worked for 15 hours.

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10c^2-60cd +80d^2

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this  \\ is \\ because...

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