Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer:
i think 50 25 or 75 cents
Step-by-step explanation:
Answer:
Hey there!
Step-by-step explanation:
This is ur answer....
<h2><em>60 + 120 = 180</em></h2>
<h2><em>DEF = 180</em></h2>
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Answer:
y=x+4
Step-by-step explanation:
from the graph
I think it's ×=2.5 or it's x=1 or it's x= 19