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4 years ago

A 6,000.00 principal earns 8% interest, compounded semiannually twice per year after 35 years what is it

1 answer:

6 0

A=p (1+r/k)^kn
A future value
P present value 6000
R interest rate 0.08
K compounded semiannual 2
N time 35years

A=6,000×(1+0.08÷2)^(2×35)
A=93,429.71

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A cone has a volume of 942 in.³ and a height of 9 inches what is the radius of the cone use 3.14 for pie

bija089 [108]

Answer:

r = 51.96 inches

Step-by-step explanation:

$V_{cone} = \pi {r}^{2} h \\ \\ \implies \: r^{2} = \frac{V_{cone}}{\pi h } \\ \\ \implies \: r^{2} = \frac{942}{3.14 {(9) } }\\ \\ \implies \: r^{2} = \frac{942}{3.14 {(9) } } \\ \\ \implies \: r^{2} =2700 \\ \\ \implies \: r= \sqrt{2700} \\ \\ \implies \: r=51.96 \: inches$

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2 years ago

You earned a 90% on my science test you answer 18 questions correctly how many questions were on the test

Gre4nikov [31]

90% x 18 = 16.2

Therefore, you answered about 16 questions correctly out of 18.

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4 years ago

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Help me i think it’s c

Andrei [34K]

Answer: Graph B

=====================================================

Explanation:

Point A appears to be at (2.5, -1)

If we shift 6 units to the left, then we subtract 6 from the x coordinate. So the new x coordinate is now 2.5-6 = -3.5

If we shift 4 units up, then we add 4 to the y coordinate to go from -1 to -1+4 = 3

Overall, the point A(2.5, -1) moves to A'(-3.5, 3)

Graph B is the answer because of this. The other points B and C will follow the same pattern as point A does.

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3 years ago

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Evaluate the series

dalvyx [7]

Answer:

the value of the series;

$\sum_{k=1}^{6}(25-k^2) = 59$

C) 59

Step-by-step explanation:

Recall that;

$\sum_{1}^{n}a_n = a_1+a_2+...+a_n\\$

Therefore, we can evaluate the series;

$\sum_{k=1}^{6}(25-k^2)$

by summing the values of the series within that interval.

the values of the series are evaluated by substituting the corresponding values of k into the equation.

$\sum_{k=1}^{6}(25-k^2) =(25-1^2)+(25-2^2)+(25-3^2)+(25-4^2)+(25-5^2)+(25-6^2)\\\sum_{k=1}^{6}(25-k^2) =(25-1)+(25-4)+(25-9)+(25-16)+(25-25)+(25-36)\\\sum_{k=1}^{6}(25-k^2) =24+21+16+9+0+(-11)\\\sum_{k=1}^{6}(25-k^2) = 59\\$

So, the value of the series;

$\sum_{k=1}^{6}(25-k^2) = 59$

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4 years ago

Riccardo Frierson deposits $1,200 in savings account. The account pays a 3.5% annual interest rate. He makes no other deposits o

jonny [76]

Answer: 25

Step-by-step explanation:

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2 years ago