Answer:
0.767 moles of ammonium phosphate are produced
Explanation:
The reaction of ammona (NH3), with phosphoric acid is:
3 NH3 + H3PO4 → (NH4)3PO4
<em>Where 3 moles of ammonia reacts per mole of H3PO4 to produce 1 mole of ammonium phosphate.</em>
<em />
If 2.3 moles of ammonia reacts, the moles of ammonium phosphate produced if phosphoric acid is in excess are:
2.3 moles NH3 * (1 mole (NH4)3PO4 / 3 moles NH3) =
<h3>0.767 moles of ammonium phosphate are produced</h3>
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K₂CrO₄(aq) + Ba(NO₃)₂(aq) = BaCrO₄(s) + 2KNO₃(aq)
2K⁺ + CrO₄²⁻ + Ba²⁺ + 2NO₃⁻ = BaCrO₄ + 2K⁺ + 2NO₃⁻
spectator ions: K⁺, NO₃⁻
.<span>The most common theme found in the Harlem Renaissance art was that of presenting a well educated, sophisticated African-American.
Explanation:
</span>Additionally, the Harlem Renaissance<span> was viewed primarily as a literary movement </span>targeted<span> in </span>Harlem<span> and growing out of the black migration </span>and therefore the<span> emergence of </span>Harlem because of the<span> premier black metropolis </span>within u. s.<span> Music and theatre were mentioned </span>in brief<span>, </span>a lot of<span> as background </span>and native<span> colour, as providing innovation for poetry </span>and local<span> colour for fiction </span>Harlem Renaissance<span>, an </span>efflorescence of<span> African </span>yank<span> culture, </span>significantly within the inventive<span> arts, </span>and therefore the most powerful movement<span> in African </span>yank<span> literary history. some common themes were: alienation, </span>position<span>, use </span>of people<span> material, use of the Blues tradition.</span>
Answer:
Mitosis is common to all eukaryotes; during this process, a parent cell splits into two genetically identical daughter cells, each of which contains the same number of chromosomes as the parent cell.During meiosis, the cells needed for sexual reproduction divide to produce new cells called gametes.
From reliable sources in the web, it may be searched that the specific heat of copper is approximately equal to 0.385 J/gC. The amount of heat that is required to raise a certain amount by certain number of degrees is given in the equation,
H = mcpdT
where H is heat, m is mass, cp is specific heat, and dT is temperature difference. Substituting the known values,
186,000 J = (m)(0.385 J/gC)(285C)
m = 1695.15 g
