All categories

2 years ago

What is the algabric way to find the area of a triangle

1 answer:

4 0

The parameters for computing the area of triangle is first listed out and the expression for the area of triangle was used to find the algebraic method

<h3>Area of Triangle</h3>

Parameters for find the area of triangle are

Base

Height

Let the base be x, and let the height be y

We know that the expression for the area of triangle is given as

Area = 1/2 (Bass* Height)

Substituting our parameters we have

Area = 1/2*x*y

Learn more about area of triangle here:

brainly.com/question/17335144

You might be interested in

A game room has a floor that is 125 feet by 30 feet. A scale drawing of the floor on grid paper uses a scale of 3 units:5 feet.

crimeas [40]

It would be 75 units in length and 18 units in width.

7 0

3 years ago

Find the area each sector. Do Not round. Part 1. NO LINKS!!

sladkih [1.3K]

Answer:

$\textsf{Area of a sector (angle in degrees)}=\dfrac{\theta}{360 \textdegree}\pi r^2$

$\textsf{Area of a sector (angle in radians)}=\dfrac12r^2\theta$

17) Given:

$\theta$ = 240°
r = 16 ft

$\textsf{Area of a sector}=\dfrac{240}{360}\pi \cdot 16^2=\dfrac{512}{3}\pi \textsf{ ft}^2$

19) Given:

$\theta=\dfrac{3 \pi}{2}$
r = 14 cm

$\textsf{Area of a sector}=\dfrac12\cdot14^2 \cdot \dfrac{3\pi}{2}=147 \pi \textsf{ cm}^2$

21) Given:

$\theta=\dfrac{ \pi}{2}$
r = 10 mi

$\textsf{Area of a sector}=\dfrac12\cdot10^2 \cdot \dfrac{\pi}{2}=25 \pi \textsf{ mi}^2$

23) Given:

$\theta$ = 60°
r = 7 km

$\textsf{Area of a sector}=\dfrac{60}{360}\pi \cdot 7^2=\dfrac{49}{6}\pi \textsf{ km}^2$

3 0

2 years ago

Complete the square: x^2-8x+21=6 Please show work

mina [271]

Answer:

x=5 and 3

Step-by-step explanation:

x^2-8x+21=6

x^2-8x+21+16=6+16

(x-4)^2=1

(x-4)=±1, x=5 and 3

5 0

3 years ago

Read 2 more answers

Kindly answer this one. Thank you.

steposvetlana [31]

Answer:

See below.

Step-by-step explanation:

I'm assuming these questions are about the Midline Theorem (segment AL joins the midpoints of the non-parallel sides.

♦ The midline's length is the average of the lengths of the top and bottom parallel sides.

$AL=\frac{OR+CE}{2}$

Use this equation and substitute values given in each problem, then solve for the missing information.

1. AL = x, CE = 9, OR = 5

$x=\frac{9+5}{2}=7$

2. AL = m - 4, CE = 15, OR = 17

$m-4=\frac{15+17}{2}=16\\\\m-4=16\\\\\\m=20\\\\AL=20-4=16$

3. OR = y + 5, AL = 15, CE = 18

$15=\frac{(y+5)+18}{2}\\\\15=\frac{y+23}{2}\\\\30=y+23\\\\7=y\\\\OR = 7+5=12$

4 0

2 years ago

82.8 cm measured to the nearest tenth of a cm what's the answer ;-)

patriot [66]

Answer:

I think it 8.0 cm

7 0

2 years ago

Read 2 more answers