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miss Akunina [59]
2 years ago
9

What is the algabric way to find the area of a triangle

Mathematics
1 answer:
mash [69]2 years ago
4 0

The parameters for computing the area of triangle is first listed out and the expression for the area of triangle was used to find the algebraic method

<h3>Area of Triangle</h3>

Parameters for find the area of triangle are

  • Base
  • Height

Let the base be x, and let the height be y

We know that the expression for the area of triangle is given as

Area = 1/2 (Bass* Height)

Substituting our parameters we have

Area = 1/2*x*y

Learn more about area of triangle here:

brainly.com/question/17335144

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Can u guys pretty please help
erastova [34]
It should be A and D, no promises
7 0
3 years ago
Write each expression as an algebraic​ (nontrigonometric) expression in​ u, u &gt; 0.
max2010maxim [7]

Answer:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

Step-by-step explanation:

We want to write the trignometric expression:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)

Take the secant of both sides:

\displaystyle \sec(\theta)=\frac{u}{10}

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}

By substitutition:

\displaystyle= \sin(2\theta)

Using an double-angle identity:

=2\sin(\theta)\cos(\theta)

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)

Simplify. Therefore:

\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0

4 0
3 years ago
Kevin is 3 years older than brendon two years ago Kevin was 4 times as old as brendon . How old is Kevin now
Tpy6a [65]

Answer:

  Kevin is 6

Step-by-step explanation:

Let k represent Kevin's age now. Then Brendon's age now is (k-3). Two years ago the relationship of their ages was ...

  k-2 = 4((k-3) -2)

  k -2 = 4k -20 . . . . . eliminate parentheses, collect terms

  3k = 18 . . . . . . . . . . add 20-k

  k = 6 . . . . . . . . . . . . divide by 3

Kevin is 6 now.

4 0
3 years ago
List the following expressions in order from least to greatest value.
Sonja [21]
V57 v3 is Keats becuase it’s math and not why it’s not math it’s math just holy math with gif
8 0
3 years ago
Read 2 more answers
Does anyone know how to do this?
Anni [7]
Cool You have a good software! I’m using this space so that you can mark the next person brainliest!
8 0
3 years ago
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