Answer:
C.1/6
Step-by-step explanation:
Initially the box has four $1 and six $5 bills. The probability of selecting a $5 bill in the first trial would be given as;
(number of $5 bills) / (total number of bills)
= (6)/(4+6) = 3/5
If in the first attempt we actually pick a $5 bill, the number of $5 bills will reduce by one to 5. Now, the probability of picking a $5 bill in the second attempt will be given as;
(new number of $5 bills) / (new total number of bills)
= (5)/(4+5) = 5/9
The new number of $5 bills will now be; 6 - 2 = 4 since we have already picked 2 without replacing them.
Now, the probability of picking a $5 bill in the third attempt will be given as;
(new number of $5 bills) / (new total number of bills)
= (4)/(4+4) = 1/2
Since the three attempts are independent, the probability of picking all three $5 bills is;
3/5 * 5/9 * 1/2 = 1/6
(−2h+9)(9h−2)
-18h^2 + 4h + 81h - 18
Answer: -18h^2 + 85h - 18
Answer:
0.4h ; 60 - h ;18 - 0.3h ; 0.1h + 18
Step-by-step explanation:
Given that:
Old house blend = 40% Columbian beans
New house blend = 30% Columbian beans
h = number of pounds of old house blend
a.) pound of columbian bean in old house blend :
40% of h = 0.4h
b.) pound of new blend poured into the bean:
Size of bin = 60 pound
Size of bin - pound of old house blend
(60 - h)
c. Amount of columbian bean in pound of new house blend :
30% of (60 - h)
0.3 * (60 - h)
18 - 0.3h
D.) Amount of columbian bean in 60 pound bin
(Pound of columbian bean in old house blend + pound of Columbian bean in New house blend)
0.4h + (18 - 0.3h)
0.4h + 18 - 0.3h
0.1h + 18
Answer:
16
Step-by-step explanation: