Answer:
112
Step-by-step explanation:
So, we know that a triangle's sides must add up to have a sum of 180. If you add up your given lengths and you should get 47, not including x. Then if you look at the left side/the one without a given length and it should be identical to the 21, so you know that side is 21. So now add 21 to 47, you should get 68. Finally, you subtract 68 from 180 like this: 180-68, and it should equal 112. So you're answer is 112.
Answer:
A first numbers cant be same
Answer:
A, B, D, F
Step-by-step explanation:
Matrix operations require that the matrix dimensions make sense for the operation being performed.
Matrix multiplication forms the dot product of a row in the left matrix and a column in the right matrix. That can only happen if those vectors have the same dimension. That is the number of columns in the left matrix must equal the number of rows in the right matrix.
Matrix addition or subtraction operates on corresponding terms, so the matrices must have the same dimension.
The transpose operation interchanges rows and columns, so reverses the dimension numbers. It is a defined operation for any size matrix.
<h3>Defined operations</h3>
A. CA ⇒ (4×7) × (7×2) . . . . defined
B. B -A ⇒ (7×2) -(7×2) . . . . defined
C. B -C ⇒ (7×2) -(4×7) . . . undefined
D. AB' ⇒ (7×2) × (2×7) . . . . defined
E. AC ⇒ (7×2) × (4×7) . . . undefined
F. C' ⇒ (7×4) . . . . defined
There are 20 numbers in the set.
Given,
Set of numbers is 120
one number is increased by 300
and, mean increases to 135.
To find the how many numbers are in the set?
Now, According to the question:
Let the number of numbers be 'n'
Then, (sum of numbers)/n = 120
or, old sum = 120n
if one number is increased by 300, the new sum = (old sum + 300)
Then, (new sum)/ n= 135
or new sum = 135n = old sum + 300 = 120n + 300
The equation will be:
135n = 120n + 300
15n = 300
n = 20
Hence, There are 20 numbers in the set.
In the question:
The mean of a set of numbers is 120. if one number is increased by 300, the mean increases to 135.
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Answer:

Step-by-step explanation:
y = x .....(1)
.... (2)
By solving equation (1) and equation (2)


or 
x = 0, x = 1
y = 0, y = 1
A = 
A = 
A = ![\frac{2}{3}[x^\frac{3}{2}]_{0}^{1}-\frac{1}{2}[x^2]_{0}^{1}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D%5Bx%5E%5Cfrac%7B3%7D%7B2%7D%5D_%7B0%7D%5E%7B1%7D-%5Cfrac%7B1%7D%7B2%7D%5Bx%5E2%5D_%7B0%7D%5E%7B1%7D)
A = 
A = 