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valentinak56 [21]
2 years ago
9

Brody drives 180 km in two hours. How fast is he travelling? should be in km/hour)

Physics
1 answer:
Finger [1]2 years ago
3 0

Answer:

90 km/h

Explanation:

we just divide the distance by the time to get the speed.

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A pilot heads her jet due east. The jet has a speed of 425 mi/h relative to the air (in other words, if the air were still, the
Elza [17]

Answer:

The resultant velocity of the jet as a vector in component form 426.87 mi/hr 5.36 degrees North.

Explanation:

Vectors are quantities that have their magnitude and direction .

Sketching out the problem given, by using straight lines to represent each of the vectors, we will have a right angled triangle as shown below.

The solution can be obtained by applying Pythagoras theorem to

resolve the vectors.

Velocity of jet plane = 425 mi/hr

velocity of air = 40 mi/hr

Resultant of the vectors =\sqrt[]{425^{2}+40^{2}}=426.87 mi/hr

Vector direction =tan^{-1}(\frac{40}{425})= 5.36 degrees

hence the velocity is 426.87 mi/hr in a direction 5.36 degrees inclined Northward

5 0
3 years ago
A 500 kg dragster accelerates from rest to a final speed of 100 m/s in 400 m (about a quarter of a mile) and encounters an avera
Fantom [35]
In order to accelerate the dragster at a speed v_f = 100 m/s, its engine must do a work equal to the increase in kinetic energy of the dragster. Since it starts from rest, the initial kinetic energy is zero, so the work done by the engine to accelerate the dragster to 100 m/s is
W= K_f - K_i = K_f =  \frac{1}{2}mv_f^2=2.5 \cdot 10^6 J

however, we must take into account also the fact that there is a frictional force doing work against the dragster, and the work done by the frictional force is:
W_f = F_f d = -(1200 N)(400 m)= -4.8 \cdot 10^5 J
and the sign is negative because the frictional force acts against the direction of motion of the dragster.

This means that the total work done by the dragster engine is equal to the work done to accelerate the dragster plus the energy lost because of the frictional force, which is -W_f:
W_t = W + (-W_f)=2.5 \cdot 10^6 J+4.8 \cdot 10^5 J=2.98 \cdot 10^6 J

So, the power delivered by the engine is the total work divided by the time, t=7.30 s:
P= \frac{W}{t}= \frac{2.98 \cdot 10^6 J}{7.30 s}=4.08 \cdot 10^6 W

And since 1 horsepower is equal to 746 W, we can rewrite the power as
P=4.08 \cdot 10^6 W \cdot  \frac{1 hp}{746 W} =547 hp



3 0
4 years ago
Read 2 more answers
ASAP 1-5 question plzz helppp, mark Brainliest if you answer all 5 questions
podryga [215]

Answer:

a,b,d,b, false

Explanation:

7 0
3 years ago
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Four identical 2.5 mF capacitors are connected together electrically. What is the greatest possible capacitance of the combinati
MrRa [10]

When capacitors are in PARALLEL, they add up. (like resistors in series)

If you connect these four capacitors in parallel, the combination behaves like a single capacitor of (4 x 2.5) = 10 mF.

That's the greatest capacitance you can make with these four pieces.

7 0
3 years ago
A steel cable with Cross Sectional Area 3.00cm² has an elastic limit of 2.40 x 10^8pascals. Find the maximum upward acceleration
bazaltina [42]

Answer:

Stress = F / A       force per unit area

A = 3.00 cm^2 = 3 E-4  m^2

F = 2.4E8 N/m^2 * 3E-4 m^2 = 7.2E4 N    max force applied

F/3 = 2.4E4 N  if force not to exceed limit   (= f)

f = M a

a = 2.4 E4 N / 1.2 E3 kg = 20 m / s^2      about 2 g

3 0
3 years ago
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