948 or 9.48 x 10^2
There are two sets of rules for significant figures
• One set for addition and subtraction
• Another set for multiplication and division
You used the set for multiplication and division.
This problem involves addition and subtraction, and the rule is
The number of places after the decimal point in the answer must be <em>no greater than the number of decimal places in every term</em> in the sum.
Thus, we have
78.9
+890.43
-21.
= 948.33
The "21" term has the fewest digits after the decimal point (none), so the answer must have no digits after the decimal point.
To the correct answer is 948 = 9.48 x 10^2. It has three significant figures.
Answer:
because of catenation of carbon.
Explanation:
Catenation is the binding of an element to its self through covalent bonds to form chain or ring molecules. carbon is able to form continuous links with other carbon atoms which is the reason for the existence of a large number of organic compounds.
Given reactions:
(A) 6CO2(g) + 6H2O(l) + sunlight → C6H12O6(aq) + 6O2(g)
(B) 2H2(g) + O2(g) → 2H2O(g) + energy
Exothermic reactions are those which proceed with the release of heat/energy. In contrast, endothermic reactions proceed with the absorption of energy in the form of heat or light.
Since reaction A required sunlight, it is endothermic. Reaction B releases energy, hence exothermic
Ans: (B)
A is endothermic
B is exothermic
Answer:
The core of Jupiter and Saturn is made up of rock,metal and hydrogen compounds, while the core of Uranus and Neptune is made up of rock,metals,water, methane, and ammonia.
Explanation:
The Jovian planets include, Jupiter, Saturn, Uranus, and Neptune. These planets when compared to terrestrial planets are small, with dense cores and surrounded by layers of gas.
Answer:- The natural abundance of
is 0.478 or 47.8% and
is 0.522 or 52.2% .
Solution:- Average atomic mass of an element is calculated from the atomic masses of it's isotopes and their abundances using the formula:
Average atomic mass = mass of first isotope(abundance) + mass of second isotope(abundance)
We have been given with atomic masses for
and
as 150.919860 and 152.921243 amu, respectively. Average atomic mass of Eu is 151.964 amu.
Sum of natural abundances of isotopes of an element is always 1. If we assume the abundance of
as n then the abundance of
would be 1-n .
Let's plug in the values in the formula:
![151.964=150.919860(n)+152.921243(1-n)](https://tex.z-dn.net/?f=151.964%3D150.919860%28n%29%2B152.921243%281-n%29)
151.964=150.919860n+152.921243-152.921243n
on keeping similar terms on same side:
![151.964-152.921243=150.919860n-152.921243n](https://tex.z-dn.net/?f=151.964-152.921243%3D150.919860n-152.921243n)
![-0.957243=-2.001383n](https://tex.z-dn.net/?f=-0.957243%3D-2.001383n)
negative sign is on both sides so it is canceled:
![0.957243=2.001383n](https://tex.z-dn.net/?f=0.957243%3D2.001383n)
![n=\frac{0.957243}{2.001383}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B0.957243%7D%7B2.001383%7D)
![n=0.478](https://tex.z-dn.net/?f=n%3D0.478)
The abundance of
is 0.478 which is 47.8%.
The abundance of
is = ![1-0.478](https://tex.z-dn.net/?f=1-0.478)
= 0.522 which is 52.2%
Hence, the natural abundance of
is 0.478 or 47.8% and
is 0.522 or 52.2% .