Answer:
Alkali metal hydroxides can be used to test the identity of metals in certain salts. The colour of the precipitate will help identify the metal : Calcium hydroxide is soluble; no precipitate is formed.
The average kinetic energy of an ideal gas is calculated as
KE_avg = 3/2 kT
where T is the temperature in Kelvin and k=R/N_A; R is the universal gas constant and N_A is the number of moles.
Thus, upon substitution we get
KE_avg = 3/2(8.314/1)(100+273)
KE_avg = 3/2(8.314)(373)
KE_avg = 4651.683
The average kinetic energy of 1 mole of a gas at 100 degree Celsius is 4651.683 J.
Explanation:
1) 
Energy will be absorbed by the Cs(s) to get converted into Cs(g). In order to break the strong association of particles present in solid to convert it into gaseous state energy will be needed. So, energy will be absorbed by the Cs solid in this reaction.
2) 
Energy will be absorbed by 
gas in order to break bond between two Cl atoms to form isolated(alone) single chlorine atom.So, the energy will be absorbed by the chlorine gas molecule in this reaction.
3) 
Energy will be absorbed by the Cs(g) to get converted into 
cation. In order to remove an electron from the outer most shell of Cs atom energy will be required by Cs atom, So, energy will be absorbed in this reaction.
4) 
Energy will get release in formation of 
anion from Cl atom in gaseous state. Chlorine atom need one electron to attain noble gas configuration. So, when an electron is added to the outer most shell of chlorine it attains stability of fully filled outermost shell by which it releases energy on addition of an electron.
5) 
Energy will get release on formation of CsCl(s) from
cation and anion. since both are oppositely charged ion and due to strong electrostatic interaction will get converted into stable molecule of CsCl (s) with release in an energy.
From the gas law, PV=nRT we can say that P(pressure), V(volume) and T (temperature) are related to each other. The initial volume of sample is 408 ml
Given that initial volume of the sample = V1
initial pressure of the sample = 0.92atm
initial temperature of the sample = 23.2oC
Final pressure of the sample = 1.3atm
Final temperature of the sample = 40.1 oC
Final volume of the sample = 500ml = 0.5L
Using the relation P1V1/T1 = P2V2/T2
V1 = 1.3x0.5x23.2/40.1x0.92 = 15.08/36.892 = 0.408
Hence the initial volume of sample = 408 ml
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Answer:
0.056moles HF and 0.70M
Explanation:
When a strong acid is added to a buffer, the acid reacts with the conjugate base.
In the system, NaF and HF, weak acid is HF and conjugate base is NaF. The reaction of NaF with HCl (Strong acid) is:
NaF + HCl → HF + NaCl
Initial moles of NaF and HF in 60.0mL of solution are:
NaF:
0.0600L × (0.80mol / L)= 0.048 moles NaF
HF:
0.0600L × (0.80mol / L)= 0.048 moles HF
Then, the added moles of HCl are:
0.0200L × (0.40mol / L) = 0.008 moles HCl.
Thus, after the reaction, moles of HF produced are 0.008 moles + the initial 0.048moles of HF, moles of HF are:
<em>0.056moles HF</em>
<em></em>
In 20.0mL + 60.0mL = 80.0mL = 0.0800L, molarity of HF is:
0.056mol HF / 0.0800L = <em>0.70M</em>
