0.89 m =___________mg?
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<u>Answer:</u> The equilibrium molarity of oxygen gas is 7.1 M
<u>Explanation:</u>
We are given:
Moles of oxygen gas = 1.3 mole
Moles of NO = 1.5 moles
Volume of the flask = 250 mL = 0.250 L (Conversion factor: 1 L = 1000 mL)
To calculate the molarity, we use the equation:
Molarity of oxygen gas =
Molarity of NO =
The chemical equation follows:
Initial: 5.2 - 6.0
At eqllm: 5.2+x +x 6.0-2x
The expression of for above equation follows:
(Assuming)
Putting values in above equation, we get:
Neglecting the value of x = 5.4 because this cannot be greater than the initial value.
Concentration of oxygen gas at equilibrium = (5.2 + x) = 5.2 + 1.9 = 7.1 M
Hence, the equilibrium molarity of oxygen gas is 7.1 M