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ASHA 777 [7]
3 years ago
11

I need help with this question. Thank you.

Chemistry
1 answer:
marishachu [46]3 years ago
3 0
There are 76 atoms in total
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Need help please!!!!!!!!
dsp73
Long wavelengths and low frequencies
5 0
3 years ago
A gas has a pressure of 8.5atm and occupies 24L at 25∘C. What volume (in liters) will the gas occupy if the pressure is increase
Vesna [10]

The volume (in liters) that the gas will occupy if the pressure is increased to 13.5 atm and the temperature is decreased to 15 °C is 15 L

From the question given above, the following data were obtained:

Initial pressure (P₁) = 8.5 atm

Initial volume (V₁) = 24 L

Initial temperature (T₁) = 25 °C = 25 + 273 = 298 K

Final pressure (P₂) = 13.5 atm

Final temperature (T₂) = 15 °C = 15 + 273 = 288 K

<h3>Final volume (V₂) =? </h3>

  • The final volume of the gas can be obtained by using the combined gas equation as illustrated below:

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\\\frac{8.5 * 24}{298}  = \frac{13.5 * V_{2}}{288}\\\\ \frac{204}{298} = \frac{13.5 * V_{2}}{288}\\\\

Cross multiply

298 × 13.5 × V₂ = 204 × 288

4023 × V₂ = 58752

Divide both side by 4023

V_{2} = \frac{58752}{4023}\\\\

<h3>V₂ = 15 L </h3>

Therefore, the final volume of the gas is 15 L

Learn more: brainly.com/question/25547148

3 0
2 years ago
15. Within a voltaic cell,___
kobusy [5.1K]

Answer:

B. oxidation; reduction

Explanation:

A voltaic cell is electro-chemical cell in which chemical energy is converted into electrical energy.

1. This cell utilizes chemical reaction to generate electric.\

2. there two electrode anode and cathode

3. At Anode oxidation occurs

4. At cathode reduction occurs

5. chemical is present in the cell which is electrolyte which completes the circuit of the voltaic cell.

  • oxidation is the process in which there is loss of electrons
  • Reduction is the process in which there is gain of electrons

___________________________________________________

Based on above discussion

At anode oxidation takes place

At cathode reduction takes place.

Hence, correct option is B. oxidation; reduction

7 0
3 years ago
At a certain temperature, Kc = 0.0500 and ∆H = +39.0 kJ for the reaction below, 2 MgCl2(s) + O2(g) → 2MgO(s) + Cl2(g) Calculate
Minchanka [31]

Explanation:

Since, it is shown that the reaction has been reversed. Therefore, value of K_{c} will become \frac{1}{K_{c}}.

Hence, new K_{c'} = \frac{1}{K_{c}}

                                      = \frac{1}{0.0500}

                                      = 20

Also, the number of moles of each reactant has been halved. So, K_{c''} for the reaction MgO(s) + \frac{1}{2}Cl2(g) → MgCl_{2}(s) + \frac{1}{2} O2(g) will also get halved.

Therefore,     K_{c''}  = K_{c'} = (20)^{0.5}

                               = 4.47

As the value of \Delta H is given as +39.0 kJ. So, it means that the reaction is endothermic in nature. So, energy of reactants will be more than the products. Hence, according to Le Chatelier's principle reaction will move in the forward direction.

As a result, K_{c} will also increase with increase in temperature.

6 0
3 years ago
11.23 mm = ____ m 1,123 m 0.01123 m 0.1123 m 11,230 m
kaheart [24]
For every meter, the equivalent measurements is 1000 millimeters. Hence in the problem where the number of millimeters is given, we divide the number by 1000 to get the number of meters. The answer here is 0.01123 m.
3 0
3 years ago
Read 2 more answers
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