All categories

2 years ago

The illustration below shows the graph of

Mathematics

1 answer:

ExtremeBDS [4]2 years ago

5 0

Answer:

This is the graph of a {\text{nonlinear function}}nonlinear functionstart text, n, o, n, l, i, n, e, a, r, space, f, u, n, c, t, i, o, n, end text.

The yyy-intercept of the graph is the function value y={{-6}}y=−6y, equals, minus, 6.

The xxx-intercepts of the graph are located at x={2}x=2x, equals, 2 and x={6}x=6x, equals, 6.

The greatest value of yyy is y={2}y=2y, equals, 2, and it occurs when x={4}x=4x, equals, 4.

For xxx between x=2x=2x, equals, 2 and x=6x=6x, equals, 6, the function value {y \, {\geq } 0}y≥0y, is greater than or equal to, 0.

Step-by-step explanation:

Let's use the graph to complete the sentences one by one.

Hint #22 / 7

A function with a constant rate of change produces a graph that is a line, and we say the function is linear. If the rate of change of the function is not constant, the graph will not be a line, and we say the function is nonlinear.

The graph shown is not a line. Therefore, we are looking at the graph of a nonlinear function.

Hint #33 / 7

The yyy-intercept of a graph is the value of the function when \red{x=0}x=0start color #df0030, x, equals, 0, end color #df0030. The yyy-intercept of this graph is the function value \blue{y=-6}y=−6start color #6495ed, y, equals, minus, 6, end color #6495ed.

Hint #44 / 7

The xxx-intercepts of a graph are the values of \red{x}xstart color #df0030, x, end color #df0030 for which \blue{y=0}y=0start color #6495ed, y, equals, 0, end color #6495ed. The xxx-intercepts of this graph are located at \red{x=2}x=2start color #df0030, x, equals, 2, end color #df0030 and \red{x=6}x=6start color #df0030, x, equals, 6, end color #df0030.

Hint #55 / 7

The maximum value of \blue{y}ystart color #6495ed, y, end color #6495ed occurs at the top of the bump in the graph. The coordinates of the top of the bump are (\red{4},\blue{2})(4,2)left parenthesis, start color #df0030, 4, end color #df0030, comma, start color #6495ed, 2, end color #6495ed, right parenthesis. Therefore, the maximum value is \blue{y=2}y=2start color #6495ed, y, equals, 2, end color #6495ed, and it occurs when \red{x=4}x=4start color #df0030, x, equals, 4, end color #df0030.

Hint #66 / 7

The graph of the function is above the xxx-axis for values of \red{x}xstart color #df0030, x, end color #df0030 between \red{x=2}x=2start color #df0030, x, equals, 2, end color #df0030 and \red{x=6}x=6start color #df0030, x, equals, 6, end color #df0030. For these values of \red{x}xstart color #df0030, x, end color #df0030, the function value y\geq 0y≥0y, is greater than or equal to, 0.

Hint #77 / 7

We can now complete the sentences:

This is the graph of a {\text{nonlinear function}}nonlinear functionstart text, n, o, n, l, i, n, e, a, r, space, f, u, n, c, t, i, o, n, end text.

The yyy-intercept of the graph is the function value y={{-6}}y=−6y, equals, minus, 6.

The xxx-intercepts of the graph are located at x={2}x=2x, equals, 2 and x={6}x=6x, equals, 6.

The greatest value of yyy is y={2}y=2y, equals, 2, and it occurs when x={4}x=4x, equals, 4.

For xxx between x=2x=2x, equals, 2 and x=6x=6x, equals, 6, the function value {y \, {\geq } 0}y≥0y, is greater than or equal to, 0.

You might be interested in

Hello pls Asap plsssss

Kay [80]

Option 3 or 4 would be your correct answer

5 0

3 years ago

Which shows the dimensions of two rectangular prisms that have volumes of 72 cm3 but different surface areas? A. 6 cm by 3 cm by

Nookie1986 [14]

To solve, lets find the volumes of all of the options...

V=l*w*h

A.
6*3*4=72cm³
12*2*3=72cm³

B.
2*4*9=72cm³
9*4*2=72cm³

C.
3*3*8=72cm³
2*6*8=96cm³

D.
6*3*4=72cm³
9*4*3=108cm³

We can conclude that C & D aren't the answer, since they contain prisms that don't have a volume of 72cm³.

Now lets solve for the surface area of A and B...

A.
sA=2(wh+lw+lh)=2(6*3+4*6+4*3)=2(18+24+12)=2(54)=108cm²
sA=2(wh+lw+lh)=2(12*2+3*12+3*2)=2(24+36+6)=2(56)=112cm²

B.
sA=2(wh+lw+lh)=2(2*4+9*2+9*4)=2(8+18+36)=2(62)=124cm²
sA=2(wh+lw+lh)=2(9*4+2*9+2*4)=2(36+18+8)=2(62)=124cm²

A is the only option with both similar volumes of 72cm³ and different surface areas...

Answer=A

3 0

3 years ago

Read 2 more answers

(4x + 10) – (-3x + 5) <br> Help

dalvyx [7]

Answer:

x= -15 or (7x+5)

Step-by-step explanation:

Simplifying

4x + 10 = 3x + -5

Reorder the terms:

10 + 4x = 3x + -5

Reorder the terms:

10 + 4x = -5 + 3x

Solving

10 + 4x = -5 + 3x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3x' to each side of the equation.

10 + 4x + -3x = -5 + 3x + -3x

Combine like terms: 4x + -3x = 1x

10 + 1x = -5 + 3x + -3x

Combine like terms: 3x + -3x = 0

10 + 1x = -5 + 0

10 + 1x = -5

Add '-10' to each side of the equation.

10 + -10 + 1x = -5 + -10

Combine like terms: 10 + -10 = 0

0 + 1x = -5 + -10

1x = -5 + -10

Combine like terms: -5 + -10 = -15

1x = -15

Divide each side by '1'.

x = -15

Simplifying

x = -15

5 0

4 years ago

Read 2 more answers

Wild fruit flies have red eyes. A recessive mutation produces white-eyed individuals. A researcher wants to assess the proportio

svlad2 [7]

Answer:

a. The conditions are met to use a large-sample confidence interval.

b. [0.048; 0.171]

c. Decision: Not reject the null hypothesis.

d. Check explanation.

Step-by-step explanation:

Hello!

You have the following study variable:

X: red-eyed fruit fly that shows to be heterozygous due to producing mixed progeny after being crossed with s white-eyed fruit fly.

n= 100

x= 11

sample proportion 'p= 0.11

Binomial criteria:

1. The number of observation of the trial is fixed (In this case n = 100)

2. Each observation in the trial is independent, this means that none of the trials will affect the probability of the next trial

3. The probability of success in the same from one trial to another (In this case our "success" is that the fruit fly show heterozygous trough its progeny)

So X≈ Bi (n;ρ)

Considering that the sample is big enough (n≥30), you can apply the Central Limit Theorem and approximate the distribution of the sample proportion to normal. So you can use the large-sample confidence interval.

b. The formula for the confidence interval is:

'p ± $Z_{1-\alpha /2}$ * $\sqrt{\frac{'p(1-'p)}{n} }$

$Z_{1-\alpha /2} = Z_{0.975} = 1.96$

0.11 ± 1.96* $\sqrt{\frac{0.11*0.89}{100} }$

[0.048; 0.171]

At a confidence level of 95%, you'd expect that the interval [0.048; 0.171] will contain the value of the population proportion of heterozygous red-eyed flies.

H₀: ρ = 0.10

H₁: ρ ≠ 0.10

α: 0.05

Z= $\frac{'p - p}{\sqrt{\frac{p(1-p)}{n} } }$

Z= $\frac{0.11 - 0.10}{\sqrt{\frac{0.10*0.90}{100} } }$

Z= 0.33

The two tailed p-value for this test is 0.7414. The p-value is greater than the level of significance so the decision is to not reject the null hypothesis.

To be able to compare a Confidence Interval several conditions shoud be met.

1) The interval and the hypothesis test should be made for the sale population parameter.

2) The hypothesis has to be two-tailed

3) Both levels (confidence and significance) should be complementary.

4) Both have to be made with the information of the same sample. (Remember that the variable is random and the values will change from sample to sample therefore it makes no sense to compare an interval and hypothesis of different samples. You could reach a wrong conclusion)

If the conditions are met, you check the calculated interval to see if it contains the value of the parameter under the null hypothesis. If the interval contains the value (In this case 0.10) then the hypothesis is to be supported. If the interval doesn't include the value, then the hypothesis is to be rejected.

I hope this helps!

7 0

3 years ago

PLEASE HELP !!!!!!!

Vlada [557]

Answer:

23,400

Step-by-step explanation:

7 0

3 years ago