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Five less than one third of a number is two more than half of the same number. Find the number.

I am Lyosha [343]

5 less (-5) than 1/3 of number (n/3) is (=) 2 more than (2+) half of the number (n/2)

-5+n/3=2+n/2
add 5 to both sides
n/3=n/2+7
times 6 both sides
2n=3n+42
minus 2n both sides
0=n+42
minus 42 boh sides
-42=n

the number is -42

the number is 18

8 0

3 years ago

Read 2 more answers

Find the markup and the selling price of the following item. Round answers to the nearest cent. A chemistry set costing $38.50,

pochemuha

In order to compute the markup, compute the percentage like this:
$38.50\times0. 32=12,32$
The markup is then $12,32.
The selling price is the sum of the cost and the markup:
$38.50+12,32=50,82$

3 0

4 years ago

X^2+8=10x complete the square

Dovator [93]

Answer:

The answer is

Step-by-step explanation:

6 0

2 years ago

Julie Has 81 pieces of jewerly. She has twice as many earrings as she has necklaces

denis-greek [22]

I'm sorry but the problem needs to be well specified

6 0

3 years ago

The Acculturation Rating Scale for Mexican Americans (ARSMA) is a psychological test that measures the degree to which Mexican A

aleksandr82 [10.1K]

Answer:

The proportion of the population used to develop the test that has scores below 1.7 is 0.063.

The proportion of the population used to develop the test that has scores between 1.7 and 2.1 is 0.0662.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The distribution of ARSMA scores in a population used to develop the test is approximately Normal with mean 3.0 and standard deviation 0.8.

This means that $\mu = 3, \sigma = 0.8$

What proportion of the population used to develop the test has scores below 1.7?

This is the pvalue of Z when X = 1.7. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1.7 - 3}{0.8}$

$Z = -1.63$

$Z = -1.63$ has a pvalue of 0.063

The proportion of the population used to develop the test that has scores below 1.7 is 0.063.

Between 1.7 and 2.1?

This is the pvalue of Z when X = 2.1 subtracted by the pvalue of Z when X = 1.7.

X = 2.1

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2.1 - 3}{0.8}$

$Z = -1.13$

$Z = -1.13$ has a pvalue of 0.1292

X = 1.7

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{1.7 - 3}{0.8}$

$Z = -1.63$

$Z = -1.63$ has a pvalue of 0.063

0.1292 - 0.063 = 0.0662

The proportion of the population used to develop the test that has scores between 1.7 and 2.1 is 0.0662.

3 0

3 years ago