Answer: The frequency of brown beetles is 0.32.
Explanation: The frequency of A1 allele is 0.8. As p+q=1, or the sum of dominant and recessive frequencies equals 1 or 100%:
1 - 0.8 = 0.2
In Hardy-Weinberg principle,

2pq represents the frequency of heterozygote individuals, so:
genotype A1A2 = 2*0.8*0.2 = 0.32.
Thus, the frequency of brown beetles (A1A2) in the population is 0.32.
Answer:
B. Meiosis I
Explanation:
In meiosis I, it starts with a diploid cell with a homologous chromosome pair. The crossing of genetic material between chromosome pairs also occurs in this stage. The alleles containing the same trait would get separated so a new combination of alleles can be produced.
Answer:
B
Explanation:
I mean, what explanation does this need?
I didn't get it ...
can you explain that question