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koban [17]
2 years ago
9

Can Someone Assist Me Please? It would be much appreciated​

Mathematics
1 answer:
hodyreva [135]2 years ago
7 0

Ya sure.... What's your doubt?

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[Will mark as brainliest]
Aleks04 [339]

The answer is: f^{-1} = 4x^2-3,\quad\text{for  } x \leq 0

The inverse of a function f(x) is another function, f^{-1}(x), with the following property:

f(f^{-1}(x)) = f^{-1}(f(x)) = x

In other words, the inverse of a function does exactly "the opposite" of what the original function does, and so if you compute them both in sequence you return to the starting point.

Think for example to a function that doubles the input, f(x)=2x, and one that halves it: f(x)= \frac{x}{2}. Their composition is clearly the identity function f(x)=x, since you consider "twice the half of something", or "half the double of something".

In general, to invert a function y=f(x), you have to solve the expression for x, writing an expression like x = g(y). If you manage to do so, then g is the inverse of f.

In your case, you have

f(x) = y = -\frac{1}{2}\sqrt{x+3}

Multiply both sides by -2 to get

-2y = \sqrt{x+3}

Square both sides to get

4y^2 = x+3

Finally, subtract 3 from both sides to get

x = 4y^2 - 3

Since the name of the variables doesn't really have a meaning, you can say that the inverse function is

f^{-1}(x) = 4x^2 - 3

As for the domain of the inverse function, remember what we said ad the beginning: if the original function goes from set A (domain) to set B (codomain), then the inverse function goes from set B (domain) to set A (codomain). This means that the inverse function is defined on an element in B if and only if that element belongs to the range of the original function, i.e. the set of the elements of the codomain b \in B such that there exists a \in A : f(a)=b. So, we need the range of f(x).

We know that the range of g(x)=\sqrt{x} is [0,\infty). When you transform it to g(x)=\sqrt{x+3} you simply translate the graph horizontally, so the range doesn't change. But when you multiply the function times -\frac{1}{2} you affect both extrema of the range, turning it into (-\infty,0], which you can simply write as x \leq 0

4 0
2 years ago
If the temperature outside is 60 degrees at 6 pm and then drops by 15% at 10 pm, what is the temperature at 10 pm?
Zolol [24]

Answer:

51 degrees

Step-by-step explanation:=Given data

Temperature at 6pm = 60 degrees

percent drop= 15%

= 15/100*60

=0.15*60

=9 degrees

Hence the temperature at 10 pm is 60-9= 51 degrees

6 0
2 years ago
1,-4,-9,-14,-19 what’s the 5th term
wlad13 [49]

Answer:

-24

Step-by-step explanation:

goes by -5

6 0
3 years ago
Read 2 more answers
Please helpppppp! WILL GIVE BRAINLIEST!!!
frosja888 [35]

Answer:

Step-by-step explanation:

Its hard  to tell the width and length from this way, but here i got 104 square inches.

3 0
2 years ago
The Cutty Sark is a famous clipper ship (look it up)! A Cutty Sark model kit advertises a scale ratio of 1: 78, a length of 45 i
lukranit [14]

Answer: If the ratio is 1:78, a) the Cutty Sark is 3510 inches long or 292.5 ft; b) the Cutty Sark is 2028 inches tall or 169 ft according to this model

Step-by-step explanation: The ratio indicates that for every inch of the model, it corresponds to 78 inches of the actual size. If the length is 45 inches for the model, it would be an equivalent of 45*78 of the actual size = 3510 inches. The same can be applied to the height. Multiplying 26 x 78, the actual size should have a height of 2028 inches.

8 0
3 years ago
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