Answer:
Step-by-step explanation:
We are told the school sold raffle tickets, and each ticket has a digit either 1, 2, or 3. The school also sold 2 tickets with the number 000.
Therefore we have the following raffle tickets:
123
132
213
231
312
321
000
000
From the given information, we can deduce that the school sold 8 tickets and only one ticket can contain the number arrangement of 123, but 000 appeared twice.
Probability of 123 to be picked=
1/8 => 0.125
Probability of 000 to be picked=
2/8 => 0.25
Since the probability of 000 to be picked is greater than 123, a ticket number of 000 is more likely to be picked
First, you add 36 to both sides to get rid of -36. Then, the right side turns to 44 when add 8 and 36 together. Finally, your final answer is x<44
The correct answer would be A 355.5
If you take the base number of 35.55 and multiply is by 100 it should be 3,555 cm not 355.5 cm
Try this solution:
1. if 1st number is 'x', the 2d number is 'y', then it is possible to make up the system of two equation according to the condition:

2. one number is 11, another number is 10.
Answer:
The last one.
Step-by-step explanation: