How can I find the value of X?

Mathematics

1 answer:

BARSIC [14]2 years ago

5 0

Answer:

Step-by-step explanation:

Remark

The first thing you must do is notice that <D = <BEA. Mark it that way on your diagram.

The Second thing you need to notice is that <BEA and <A are equal because <A and <D are marked as equal.

So both the large triangle and the small one are isosceles. because 2 of the 3 angles are equal.

Now are you ready for this? That means that BA = 10 because BA is opposite one of the 2 equal angles in the small triangle. So now you are ready to set up a proportion.

Proportion

AB / AC = AE/AD

Givens

AB = 10

AC = 18

AE = 8

AD = x + 8

Solution

Substitute the Givens into the Proportion.

10/18 = 8/(x + 8) Cross multiply

10(x + 8) = 8 * 18 Simplify both sides

10x + 80 = 144 Subtract 80 from both sides

10x + 80 - 80 = 144 - 80

10x = 64 Divide by 10

10x/10 = 64/10

Answer: x = 6.4

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(0,4)<br> (3,-2)<br><br> The slope is m<br> and the y-intercept is b =

Rudiy27

Answer:

m = -2

y-intercept = 4

Step-by-step explanation:

m = y2-y1/x2-x1

m = -2-4/3-0

=-2

y=mx+b

Substitute the coordinates into the equation to find b

4=-2(0)+b

4=b

so y intercept is 4

y=-2x+4

5 0

3 years ago

Write the equation of an ellipse with a major axis of length 8 and co-vertices (0,3) and (0,-3)

alexandr1967 [171]

If the co-vertices are (0, 3) and (0, -3) where x is 0 and y has a value, then y is the minor axis. That means that the x axis is the major axis. Because of what the co-vertices are, the center of the ellipse is at the origin. The formula for an ellipse that has a horizontal major axis is $\frac{(x-h)^2}{a^2}+ \frac{(y-k)^2}{b^2}=1$ . The a value will always be larger than the b value, therefore, the a value goes under the coordinate that is the major axis. Here, its the x-axis. a is the distance that the outer edge of the ellipse is from the center. It's 8 units away from the center along the x axis and 3 units along the y axis from the center. So a = 8 and a^2 = 64; b = 3 and b^2 = 9. Our formula then is $\frac{x^2}{64}+ \frac{y^2}{9}=1$