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tester [92]
2 years ago
15

Find the angle of the sector given the radius and the area of the sector.

Mathematics
1 answer:
gregori [183]2 years ago
5 0

Answer:

270 degrees

Step-by-step explanation:

Area  \: of  \: the  \: sector  \\  \\  =  \frac{ \theta}{360 \degree} \times  \pi {r}^{2} \\  \\ 339.3 =  \frac{ \theta}{360 \degree} \times  3.14 {(12)}^{2}  \\  \\ 339.3 =  \frac{ \theta}{360 \degree} \times  3.14  \times 144 \\  \\  \theta =  \frac{339.3 \times 360 \degree}{3.14 \times 144} \\  \\  \theta =  \frac{122,148\degree}{452.16}  \\  \\  \theta= 270.143312 \degree \\  \\ \theta \approx \:  270\degree

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Find m/KMN. L 60° K 1⁰40 6x (11x+15)° N​
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Answer:

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Step-by-step explanation:

The exterior angle is the sum of the remote interior angles.

__

<h3>setup</h3>

  (11x +15)° = 60° +6x°

<h3>solution</h3>

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_____

<em>Additional comment</em>

Both the sum of interior angles and the sum of angles of a linear pair are 180°. If M represents the interior angle at vertex M, then we have ...

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This is also described by "supplements to the same angle are equal."

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