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3 years ago

Find the angle of the sector given the radius and the area of the sector.

Mathematics

1 answer:

gregori [183]3 years ago

5 0

Answer:

270 degrees

Step-by-step explanation:

$Area \: of \: the \: sector \\ \\ = \frac{ \theta}{360 \degree} \times \pi {r}^{2} \\ \\ 339.3 = \frac{ \theta}{360 \degree} \times 3.14 {(12)}^{2} \\ \\ 339.3 = \frac{ \theta}{360 \degree} \times 3.14 \times 144 \\ \\ \theta = \frac{339.3 \times 360 \degree}{3.14 \times 144} \\ \\ \theta = \frac{122,148\degree}{452.16} \\ \\ \theta= 270.143312 \degree \\ \\ \theta \approx \: 270\degree$

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Identify the unit rate in the graph.

Rufina [12.5K]

Answer:

No graph attached

Step-by-step explanation:

5 0

4 years ago

Factories: 64x3y3+8-2xy

Elena-2011 [213]

can you make the question clear so I can answer you the question.

3 0

3 years ago

First make a substitution and then use integration by parts to evaluate the integral. (Use C for the constant of integration.) x

e-lub [12.9K]

Answer:

$(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

Step-by-step explanation:

Ok, so we start by setting the integral up. The integral we need to solve is:

$\int x ln(5+x)dx$

so according to the instructions of the problem, we need to start by using some substitution. The substitution will be done as follows:

U=5+x

du=dx

x=U-5

so when substituting the integral will look like this:

$\int (U-5) ln(U)dU$

now we can go ahead and integrate by parts, remember the integration by parts formula looks like this:

$\int (pq')=pq-\int qp'$

so we must define p, q, p' and q':

p=ln U

$p'=\frac{1}{U}dU$

$q=\frac{U^{2}}{2}-5U$

q'=U-5

and now we plug these into the formula:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int \frac{\frac{U^{2}}{2}-5U}{U}dU$

Which simplifies to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\int (\frac{U}{2}-5)dU$

Which solves to:

$\int (U-5)lnUdU=(\frac{U^{2}}{2}-5U)lnU-\frac{U^{2}}{4}+5U+C$

so we can substitute U back, so we get:

$\int xln(x+5)dU=(\frac{(x+5)^{2}}{2}-5(x+5))ln(x+5)-\frac{(x+5)^{2}}{4}+5(x+5)+C$

and now we can simplify:

$\int xln(x+5)dU=(\frac{x^{2}}{2}+5x+\frac{25}{2}-25-5x)ln(5+x)-\frac{x^{2}+10x+25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}-\frac{5x}{2}-\frac{25}{4}+25+5x+C$

$\int xln(x+5)dU=(\frac{x^{2}-25}{2})ln(5+x)-\frac{x^{2}}{4}+\frac{5x}{2}+C$

notice how all the constants were combined into one big constant C.

7 0

3 years ago

(9•4)•18 = 9•(4•18)<br><br><br> A True <br> B. False

AveGali [126]

Answer:

false

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

680 times 0.0013 in standard form

sasho [114]

Answer:

8.84×10 To the power of -1

Step-by-step explanation:

stated number and decimal number is 8.84

goal: find the standard form of that number.

Defenition: (Plagarism Copyrights) The rules when writing a number in standard form is that first you write down a number between 1 and 10, then you write × 10(to the power of a number).

So 0.884 is 8.84/10

next put the numerator of 10 to 1 - 1/10

mulitiply 8.84 by 1/10-

this, the answer is multiply 8.84 by 10 to the power of -1

which is basically 8.84×10 To the power of -1

4 0

3 years ago