For the answer to the question above,
<span>V(n) = a * b^n, where V(n) shows the value of boat after n years.
V(0) = 3500
V(2) = 2000
n = 0
V(0) = a * b^0 = 3500
a = 3500
V(2) = a * b^2
2000 = 3500 * b^2
b = sqrt (2000/3500)
b ≈ 0.76
V(n) = 3500 * 0.76^n
We can check it for n = 1 which is close to 2500 in the graph:
V(1) = 3500 * (0.76)^1
V(1) = 2660
And in the graph we have V(3) ≈ 1500,
V(n) = 3500 * (0.76)^3 ≈ 1536
Now n = 9.5
V(9.5) = 3500 * (0.76)^(9.5)
V(9.5) ≈ 258</span>
(-8)^2
(-8)(-8)
64
Hope this helps!
Answer:
44.452
Step-by-step explanation:
Using the Pythagorean theorem you can use:
51^2 = 25^2 + w^2
2601 = 625 +w^2
w^2 = 1976
w = 44.452
∆volume = 4/3 *pi * (R^3 -r^3 )
= 4/3 *pi*((6)^3 -(3)^3)
= 252*pi
= 791.68 m^3
Answer:
1) gradient (00) (-2 4) = y2-y1 / 2-1 = 4/-2 = -2 m = -2/1 means = m = -2 (negative slope) 2) gradient y2-y1 / x2-x1 = 3-0 / 2-0 = 3/2 = (1 1/2)/1 m = 1 1/2 (positive slope) we use the formula y-values divided by the change in the x-values. The equation of the gradient each goes like this 1) y = -2x as y is at origin nothing else to add The equation of the gradient each goes like this 2) y = 1 1/2x The equation of the point formula 1) we take the y -y1 = m (x +x 1) = y-0 = -2x (x +0) (as m = -2) y = -2(x +0) and The equation of the point formula 2) y - 0 = m ( x +x1) y - 0 = 1 1/2( x +0) = y = 1 1/2( x +0)
