For the answer to the question above,  
<span>V(n) = a * b^n, where V(n) shows the value of boat after n years. 
V(0) = 3500 
V(2) = 2000 
n = 0 
V(0) = a * b^0 = 3500 
a = 3500 
V(2) = a * b^2 
2000 = 3500 * b^2 
b = sqrt (2000/3500) 
b ≈ 0.76 
V(n) = 3500 * 0.76^n 
We can check it for n = 1 which is close to 2500 in the graph: 
V(1) = 3500 * (0.76)^1 
V(1) = 2660 
And in the graph we have V(3) ≈ 1500, 
V(n) = 3500 * (0.76)^3 ≈ 1536 
Now n = 9.5 
V(9.5) = 3500 * (0.76)^(9.5) 
V(9.5) ≈ 258</span>
        
                    
             
        
        
        
(-8)^2
(-8)(-8)
64
Hope this helps!
        
                    
             
        
        
        
Answer:
44.452
Step-by-step explanation:
Using the Pythagorean theorem you can use:
51^2 = 25^2 + w^2
2601 = 625 +w^2
w^2 = 1976
w = 44.452
 
        
                    
             
        
        
        
∆volume = 4/3 *pi * (R^3 -r^3 ) 
= 4/3 *pi*((6)^3 -(3)^3)
= 252*pi 
= 791.68 m^3
        
                    
             
        
        
        
Answer:
1) gradient  (00) (-2 4) = y2-y1 / 2-1 = 4/-2 = -2  m = -2/1  means = m = -2  (negative slope)   2)  gradient  y2-y1 / x2-x1 = 3-0 / 2-0  = 3/2 = (1 1/2)/1   m = 1 1/2  (positive slope) we use the formula y-values divided by the change in the x-values.    The equation of the gradient each goes like this 1) y = -2x   as y is at origin nothing else to add     The equation of the gradient each goes like this 2) y = 1  1/2x     The equation of the point formula  1) we take the y -y1 = m (x +x 1)  =  y-0 = -2x (x +0)  (as m = -2) y = -2(x +0)   and  The equation of the point formula  2)  y - 0 = m ( x +x1)     y - 0 = 1 1/2( x +0)  = y = 1 1/2( x +0)