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creativ13 [48]
3 years ago
15

3. Calculate the mass of NH3 that can be produced from the reaction of 125 g of NCI:

Chemistry
1 answer:
otez555 [7]3 years ago
4 0

The mass of NH₃ : = 17.629 g

Further explanation

A reaction coefficient is a number in the chemical formula of a substance involved in the reaction equation. The reaction coefficient is useful for equalizing reagents and products.

Given

125 g NCl₃

Required

The mass of NH₃

Solution

mol NCl₃(molar mass : : 120.5 g/mol)

= 125 g : 120.5 g/mol

= 1.037

From the equation, mol ratio NCl₃ : NH₃ = 1 : 1, so mol NH₃ = 1.037

Mass NH₃(molar mass : 17 g/mol) :

= 1.037 x 17

= 17.629 g

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In one compound of lead and sulfur, there are 6.46 g of lead
timurjin [86]

Answer:

Lead to Sulfur = 2 : 1

Explanation:

Given

Represent lead with L and Sulfur with S

L1 = 6.46g for S1 = 1 g

L2= 3.23g for S2 = 1 g

Required

Determine the simple whole number ratio of L to S

Divide L1 by L2

L = L1/L2

L = 6.46g/3.23g

L = 2

Divide S1 by S2

S = 1g/1g

S = 1

Represent L and S as a ratio:

L : S = 2 : 1

Hence, the required ratio of Lead to Sulfur is 2 to 1

4 0
3 years ago
2. Florida has mild winter temperatures due to the _____?
Kaylis [27]
Due to the 3. Gulf Stream
4 0
2 years ago
Convert 0.237 μL to ml
Genrish500 [490]

Answer:

0.000237mL

Explanation:

0.237 x 10^-6L = 0.000000237L = mL

0.000237mL

4 0
3 years ago
) A technique once used by geologists to measure the density of a mineral is to mix two dense liquids in such proportions that t
sergeinik [125]

Hey there!

It is evident that the problem gives the mass of the bottle with the calcite, with water and empty, which will allow us to calculate the masses of both calcite and water. Moreover, with the given density of water, it will be possible to calculate its volume, which turns out equal to that of the calcite.

In this case, it turns out possible to solve this problem by firstly calculating the mass of calcite present into the bottle, by using its mass when empty and the mass when having the calcite:

m_{calcite}=15.4448g-12.4631g=2.9817g

Now, we calculate the volume of the calcite, which is the same to that had by water when weights 13.5441 g by using its density:

V_{calcite}=V_{water}=\frac{13.5441g-12.4631g}{0.997g/mL}=1.084mL

Thus, the density of the calcite sample will be:

\rho _{calcite}=\frac{m_{calcite}}{V_{calcite}}\\\\\rho _{calcite}=\frac{2.9817g}{1.084mL}=2.750g/mL

This result makes sense, as it sinks in chloroform but floats on bromoform as described on the last part of the problem, because this density is between 1.444 and 2.89. g/mL

Learn more:

  • brainly.com/question/12001845
  • brainly.com/question/11242138

Regards!

6 0
2 years ago
PLEASE HELP!<br><br>Why is phosphorus diamagnetic.
Tamiku [17]

I can't believe it and phosphorus diamagnetic.

5 0
4 years ago
Read 2 more answers
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