Answer:
Lead to Sulfur = 2 : 1
Explanation:
Given
Represent lead with L and Sulfur with S
L1 = 6.46g for S1 = 1 g
L2= 3.23g for S2 = 1 g
Required
Determine the simple whole number ratio of L to S
Divide L1 by L2
L = L1/L2
L = 6.46g/3.23g
L = 2
Divide S1 by S2
S = 1g/1g
S = 1
Represent L and S as a ratio:
L : S = 2 : 1
Hence, the required ratio of Lead to Sulfur is 2 to 1
Due to the 3. Gulf Stream
Answer:
0.000237mL
Explanation:
0.237 x 10^-6L = 0.000000237L = mL
0.000237mL
Hey there!
It is evident that the problem gives the mass of the bottle with the calcite, with water and empty, which will allow us to calculate the masses of both calcite and water. Moreover, with the given density of water, it will be possible to calculate its volume, which turns out equal to that of the calcite.
In this case, it turns out possible to solve this problem by firstly calculating the mass of calcite present into the bottle, by using its mass when empty and the mass when having the calcite:

Now, we calculate the volume of the calcite, which is the same to that had by water when weights 13.5441 g by using its density:

Thus, the density of the calcite sample will be:

This result makes sense, as it sinks in chloroform but floats on bromoform as described on the last part of the problem, because this density is between 1.444 and 2.89. g/mL
Learn more:
Regards!
I can't believe it and phosphorus diamagnetic.