The Big Bang probably occurred.
~30,000 B.C. North America Asian hunter-gatherers had crossed over the frozen Bering Strait to become first humans in North America.
~10,000 B.C. South America Those who crossed over on Bering Strait into North America had traveled as far south as Argentina by this point.
~6,000 B.C. Europe End of land bridge between Britain and continental Europe. Britain becomes an island.
~4,500 B.C. Brittany (France) The megalithic structures of Carnac were built.
~3,500 B.C. Wales Pentre Ifan is built.
~3,200 B.C. Ireland The Newgrange tomb is built.
Answer:
(a) ΔU = 7.2x10²
(b) W = -5.1x10²
(c) q = 5.2x10²
Explanation:
From the definition of power (p), we have:
(1)
<em>where, p: is power (J/s = W (watt)) W: is work = ΔU (J) and t: is time (s) </em>
(a) We can calculate the energy (ΔU) using equation (1):
(b) The work is related to pressure and volume by:

<em>where p: pressure and ΔV: change in volume = V final - V initial </em>
(c) By the definition of Energy, we can calculate q:
<em>where Δq: is the heat transfer </em>
I hope it helps you!
Mass of methane takne = 1.5g
moles of methane used = masss / molar mass = 1.5 / 16 = 0.094 moles
mass of water = 1000 g
Initial temperature of water = 25 C
final temperature = 37 C
specific heat of water = 4.184 J /g C
1) Heat absorbed by water = q =m• C• ΔT = 1000 X 4.184 x (37-25) = 50208 Joules
2) Heat absorbed by calorimeter = Heat capacity X ΔT = 695 X (37-25) = 8340 J
3) Total heat of combustion = heat absorbed by water + calorimeter = 50208 + 8340 = 58548 Joules
This heat is released by 0.094 moles of methane
So heat released by one mole of methane =
- 622851.06 Joules = 622.85 kJ / mole
4) standard enthalpy of combustion = -882 kJ / mole
Error = (882-622.85) X 100 / 882 = 24.84 %
The net ionic equation is shorter to use and already leaves out the electrons that transferred from the reducing agent to the oxidizing agent. Also, in some occasions the aqueous ions H+ and (or) OH- ions that help balance the net ionic charge are no longer shown in the net ionic equation.
Answer:
P₂ = 261 KPa
Explanation:
Given data:
Volume of sample = 200 mL
Initial pressure = 110 KPa
Initial temperature = 275 K
Final volume = 95 mL
Final temperature = 310 K
Final pressure = ?
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₂ = P₁V₁T₂ /T₁ V₂
P₂ = 110 KPa× 200 mL× 310 K /275 K × 95 mL
P₂ = 6820000 KPa / 26125
P₂ = 261 KPa