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bogdanovich [222]
2 years ago
5

What is the length of a rectangle if the width is

Mathematics
1 answer:
Anna11 [10]2 years ago
8 0

Answer:

What is the length of a rectangle if the width is

10 centimeters and the diagonal is 16 centimeters?

Step-by-step explanation:

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Simplify. -4 + 12 + (-9) *<br><br> PLEASE HELP REEEE
timama [110]

Step-by-step explanation:

= -4 + 12 + (-9)

= -4 + 12 - 9

= -4 + 3

= -1

6 0
2 years ago
How tall would one million pennies be in centimeters.And how do you know
Vikki [24]
One US-penny is 19 mm in diameter.

One British-penny is 20.3 in diameter.

We can make an accurate measurement of the diameters, or research on the internet.


1 milion US_pennies are

1,000,000*19 mm = 19,000,000 mm = 1,900,000 cm tall, since 1cm=10mm


1 milion British_pennies are 

1,000,000*20.3 mm = 20,300,000 mm = 2,030,000 cm tall, since 1cm=10mm  


8 0
3 years ago
QUÉ ES EL BASTA NUMÉRICO
Lemur [1.5K]

Answer:

relating to or expressed as a number or numbers.

Step-by-step explanation:

8 0
2 years ago
How to calculate a probability
Lelu [443]
Probability is calculated by comparing the odds to a certain event occurring to the number of possible events.

P=\frac{possibility-of-an-event-occuring}{number-of-total-outcomes}

For example, take a six-sided dice number 1-6 on each side. The probability of rolling a 4 would be1 in 6 or 1/6. This is because of the six possible outcomes, rolling a 4 is only one of them.

P(4)=1/6

Now take the same dice. The probability of rolling an even number is 3/6. To see why, lets look at the total possible outcomes:

1
2
3
4
5
6

Of the 6 possibilities, 3 are even numbers.

P(even)=3/6 or 1/2
6 0
3 years ago
Consider a simple example of moral hazard. Suppose that Woodrow goes into a casino to make one bet a day. The casino is very bas
Neko [114]

Answer:

The expected value of the safe bet equal $0

Step-by-step explanation:

If  

S=\left\{s_1,s_2,...,s_n\right\}

is a finite numeric sample space and

P(X=s_k)=p_k for k=1, 2,..., n

is its probability distribution, then the expected value of the distribution is defined as

E(X)=s_1P(X=s_1)+s_2P(X=s_2)+...+s_nP(X=s_n)X)

What is the expected value of the safe bet?

In the safe bet we have only two possible outcomes: head or tail. Woodrow wins $100 with head and “wins” $-100 with tail So the sample space of incomes in one bet is

S = {100,-100}

Since the coin is supposed to be fair,  

P(X=100)=0.5

P(X=-100)=0.5

and the expected value is

E(X) = 100*0.5 - 100*0.5 = 0

6 0
3 years ago
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