Solve -x= -4 fhfhfgdydgzxigzogxggdjpsisydgigdgosgis
1 answer:
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Answer:
D
Step-by-step explanation:
Using the rule of radicals
=
×
⇔
Given
×
= ×
= ×
Cancel on numerator/ denominator
= ×
= ×
Cancel on numerator/ denominator, leaving
= → D
Answer:
z=14.73
p=0.000
for 99% confidence level the null hypothesis is rejected, thus majority of us adults would not bothered if the NSA collected personal records.
Step-by-step explanation:
: Half of US adults would not bothered if the NSA collect records of personal telephone calls
: Majority of the adults would not bothered if the NSA collect records of personal telephone calls
According to the sample, z-value can be found using the formula:
z= where
- X is the adults, who would not be bothered in the survey (397)
- M is the mean of the distribution of null hypothesis (257)
- n is the sample size (514)
- p is the proportion of the sample, who said they would not bothered (
≈ 0.77)
Putting these numbers in the formula,
z=14.73 and corresponding p value is p≈0.000
Since p<0.01, for 99% confidence level we reject the null hypothesis, thus majority of us adults would not bothered if the NSA collected personal records.
Answer:
0.0032
The complete question as seen in other website:
There are 111 students in a nutrition class. The instructor must choose two students at random Students in a Nutrition Class Nutrition majors Academic Year Freshmen non-Nutrition majors 17 18 Sophomores Juniors 13 Seniors 18 Copy Data. What is the probability that a senior Nutrition major and then a junior Nutrition major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.
Step-by-step explanation:
Total number of in a nutrition class = 111 students
To determine the probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major, we would find the probability of each of them.
Let the probability of choosing a junior non-Nutrition major = Pr (j non-N)
Pr (j non-N) = (number of junior non-Nutrition major)/(total number students in nutrition class)
There are 13 number of junior non-Nutrition major
Pr (j non-N) = 13/111
Let the probability of choosing a sophomore Nutrition major = Pr (S N-major)
Pr (S N-major)= (number of sophomore Nutrition major)/(total number students in nutrition class)
There are 3 number of sophomore Nutrition major
Pr (S N-major) = 3/111
The probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major = 13/111 × 3/111
= 39/12321
= 0.0032
