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2 years ago

Find the surface area of the cube (above) using its net (below).

Mathematics

1 answer:

Hunter-Best [27]2 years ago

7 0

Answer:

$surface \: area \: ofa \: cube \: \\ area = \: 6 {a}^{2} \\ 6( {3}^{2} ) \\ 6(9) = 54$

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Arnoldo needs to write this system in slope-intercept form. Which shows how he could do that?

Jobisdone [24]

Answer:

$y = \frac{3}{2}x - 3$

$y = \frac{1}{8} x - \frac{7}{8}$

Step-by-step explanation:

The given system is

3x-2y=6

0.4(20y+15)=x

The slope intercept form is y=mx+c.

For the first equation, 3x-2y=6, we add -3x to both side -2y=-3x+6

$y = \frac{3}{2}x - 3$

For 0.4(20y+15)=x, we expand to get:

$8y + 7 = x$

$8y= x - 7$

Divide through by 8

$y = \frac{1}{8}x - \frac{7}{8}$

Therefore the system in slope-intercept form is:

$y = \frac{3}{2}x - 3$

$y = \frac{1}{8}x - \frac{7}{8}$

5 0

3 years ago

Read 2 more answers

Solve 3x + 7 > -x - 9. Show each step of your work.

Kruka [31]

Answer:

x > -4

Step-by-step explanation:

Inequalities like these are solved the same way equations are solved, except when multiplying both sides you flip the less than/greater than sign:

3x + 7 > -x -9

3x + 7 - 7 > -x -9 -7 Subtract 7 from both sides

3x > -x -16

3x + x > -x -16 + x add x to both sides

4x > -16

$\frac{4x}{4}$ > $\frac{-16}{4}$ divide both sides by 4

x > -4

In this case the inequality sign did not have to be flipped since we never multiply both sides by a negative number.

3 0

3 years ago

Sara is making a key chain using the bead design shown. What fraction of the beads in her design are either blue or red?

klio [65]

You can make a ratio of red to overall colors and then that will give you the fraction, you might have to simplify it

4 0

3 years ago

Which expressions are equivalent to 6 (–x) 2x (–7) 2x? Check all that apply. X x 6 – 7 x 2x 2 x 3 – x 2x – 4 2x x – 1 x 1.

qaws [65]

Equivalent expression is the expression which is equal to the original equation but the way of representation is different. The equivalent expression of the given expression are,

$x+x+6-7+x$

$3-x+2x-4+2x=3x-1$

Given information

The given expression in the problem is,

$6+(-x)+2x+(-7)+2x$

<h3>Equivalent expression</h3>

Equivalent expression is the expression which is equal to the original equation but the way of representation is different.

The given equation is,

$6+(-x)+2x+(-7)+2x$

As the product of the negative and positive is negative. Thus solve the equation by opening the bracket.

$6+(-x)+2x+(-7)+2x=6-x+2x-7+2x\\
6+(-x)+2x+(-7)+2x=-x+2x+2x+6-7\\
6+(-x)+2x+(-7)+2x=3x-1$

Check all the option,

1) The expression given in the option 1 is,

$x+x+6-7+x$

Solve it further,

$x+x+6-7+x=x+x+x+6-7\\
x+x+6-7+x=3x-1\\$

The result is equal to the result of the given expression. Thus the expression of the option 1 is equivalent to the expression given in the problem.

2) The expression given in the option 2 is,

$2x+2+x$

Solve it further,

$2x+2+x=2x+x+2\\2x+2+x=3x+2$

The result is not equal to the result of the given expression. Thus the expression of the option 2 is not equivalent to the expression given in the problem.

3) The expression given in the option 3 is,

$3-x+2x-4+2x$

Solve it further,

$3-x+2x-4+2x=3x-1$

The result is equal to the result of the given expression. Thus the expression of the option 3 is equivalent to the expression given in the problem.