Question

Heyyo does anyone knows how to solve this equation and the answer as well??

Answer 1

Answer:

A

Step-by-step explanation:

tanΘ = $\frac{\sqrt{3} }{3}$ , then

Θ = $tan^{-1}$ ( $\frac{\sqrt{3} }{3}$ ) = $\frac{\pi }{6}$

since tanΘ > 0 then Θ is in first / third quadrants

Θ = π + $\frac{\pi }{6}$ = $\frac{7\pi }{6}$

solution is { $\frac{\pi }{6}$ , $\frac{7\pi }{6}$ } in the interval 0 < Θ < 2π