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tiny-mole [99]
3 years ago
5

How many kilocalories are involved in the production of 33.68 g of NH3?

Chemistry
1 answer:
Lorico [155]3 years ago
3 0

I believe that the balanced chemical equation is:

3H2(g)+N2(g)→2NH3(g), ΔH = -21.9 kcal

 

We can see that 21.9 kcal of heat is released for every 2 moles of NH3.

The molar mass of NH3 is 17 g/mol, hence:

moles NH3 = 33.68 g / (17 g/mol)

moles NH3 = 1.98 mol

 

The total energy released is:

total heat = (-21.9 kcal / 2 mol) * 1.98 mol

total heat = -21.70 kcal

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<u>Osmosis </u>is the process that describes water moving through a membrane.

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Explanation:

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A 23.7 g piece of iron at 54.9°C is cooled and releases 338 J of heat. The specific heat of iron is 0.450 J/g°C.
ohaa [14]

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The heat capacity and the specific heat are related by C=cm or c=C/m. The mass m, specific heat c, change in temperature ΔT, and heat added (or subtracted) Q are related by the equation: Q=mcΔT. Values of specific heat are dependent on the properties and phase of a given substance.

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Explain the sources (SO2 &amp; NOx)
lawyer [7]

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Purification of chromium can be achieved by electrorefining chromium from an impure chromium anode onto a pure chromium cathode
miskamm [114]

Answer:

544.522 Hours

Explanation:

a) Mass = 12.5 kg = 12500 g

Now, Number of moles is given as

No of moles = Mass of Cr / Molar mass of Cr

=\frac{12500}{52}

= 240.38 moles

Cr^{3+}\Rightarrow 3 mols of electrons are required

\Rightarrow 240.38\times3 =721.14\text{mol of e-}

Converting moles of e- to coulombs of charge, (1 mol of electrons = 96500 C )

Q =721.14 mol×96500 C/mol

=69590010 of charge

We know that, Q = I×t

where Q is charge, I is current and t is time required.

\Rightarrow t =\frac{Q}{I}

=\frac{69590010}{35.5}

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3 0
3 years ago
Calculate the energy change when an electron moves from n=5 to n=7. Explain/show work please.
Korolek [52]

Answer: E = 1.55 ⋅ 10 − 19 J

Explanation:  

The energy transition will be equal to  1.55 ⋅ 10 − 1 J .  

So, you know your energy levels to be n = 5 and n = 3. Rydberg's equation will allow you calculate the wavelength of the photon emitted by the electron during this transition

1 λ  = R ⋅ ( 1 n 2 final  − 1 n 2 initial  ) , where λ - the wavelength of the emitted photon; R

- Rydberg's constant -  1.0974 ⋅ 10 7 m − 1 ; n final - the final energy level - in your case equal to 3; n initial - the initial energy level - in your case equal to 5. So, you've got all you need to solve for  λ , so 1 λ  =

1.0974 ⋅10  7 m − 1 ⋅ (....     −152    

)

1

λ

=

0.07804

⋅

10

7

m

−

1

⇒

λ

=

1.28

⋅

10

−

6

m

Since  

E

=

h

c

λ

, to calculate for the energy of this transition you'll have to multiply Rydberg's equation by  

h

⋅

c

, where

h

- Planck's constant -  

6.626

⋅

10

−

34

J

⋅

s

c

- the speed of light -  

299,792,458 m/s

So, the transition energy for your particular transition (which is part of the Paschen Series) is  

E

=

6.626

⋅

10

−

34

J

⋅

s

⋅

299,792,458

m/s

1.28

⋅

10

−

6

m

E

=

1.55

⋅

10

−

19

J

8 0
3 years ago
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