Is a function defined for a system relating several state variables or state quantities that depends only on the current equilibrium thermodynamic state of the system[1] (e.g. gas, liquid, solid, crystal, or emulsion), not the path which the system took to reach its present state. A state function describes the equilibrium state of a system, thus also describing the type of system. For example, a state function could describe an atom or molecule in a gaseous, liquid, or solid form; a heterogeneous or homogeneous mixture; and the amounts of energy required to create such systems or change them into a different equilibrium state.
Answer
B. acid + base --> salt + water
Explanation
Acids are substances that dissolve in water to produce hydrogen ions, H+.A base is a substance that dissolves in water to produce hydroxide ions, OH-.In a chemical reaction of an acid and a base, the products are a salt and water.For example when hydrocholoric acid is added to sodium hydroxide, a salt namely sodium chloride is formed with additional water.
Answer:
grams of solution = 551.98 g
Explanation:
Given data:
Percentage of solution = 32.9
Mass of solute = 181.6 g
Grams of solvent = ?
Solution:
Formula:
% = [grams of solute / grams of solution] × 100
Now we will put the values in formula.
32.9 = [ 181.6 g / grams of solution] × 100
grams of solution = 181.6 g × 100 / 32.9
grams of solution = 18160 g /32.9
grams of solution = 551.98 g
Answer:
C. A Spring Scale
Explanation:
Using process of elimination, we can quickly decide that a stopwatch and a ruler will not be useful in measuring the force. This leaves us with either the spring scale or a balance scale. A balance scale is used to compare two weights, so this is eliminated. That leaves us with a spring scale. This is because we can attached the spring scale to the car and when we let it go, we can record the force. I hope this helps!
Answer:
The answer to your question is P2 = 342 kPa
Explanation:
Data
Pressure 1 = P1 = 155 kPa
Volume 1 = V1 = 22 l
Pressure 2 = P2 = ?
Volume 2 = V2 = 10 l
Temperature = constant
Process
1.- Write the equation of the combined gas law
P1V1/T1 = P2V2/ T2
Cancel T1 and T2 because they measure the same
P1V1 = P2V2
-Solve for P2
P2 = P1V1/V2
2.- Substitution
P2 = (155 x 22) / 10
3.- Simplification
P2 = 3410 / 10
4.- Result
P2 = 342 kPa
