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2 years ago

How many kilocalories are involved in the production of 33.68 g of NH3?

Chemistry

1 answer:

Lorico [155]2 years ago

3 0

I believe that the balanced chemical equation is:

3H2(g)+N2(g)→2NH3(g), ΔH = -21.9 kcal

We can see that 21.9 kcal of heat is released for every 2 moles of NH3.

The molar mass of NH3 is 17 g/mol, hence:

moles NH3 = 33.68 g / (17 g/mol)

moles NH3 = 1.98 mol

The total energy released is:

total heat = (-21.9 kcal / 2 mol) * 1.98 mol

total heat = -21.70 kcal

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In chemistry, a raft of problems do not always provide an equation in order to be solved yet dimensional analysis can be applied, so as to obtain the desired amount in the required units.

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