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pychu [463]
3 years ago
15

How is energy passed along in the food chain and food web PLEASE HELP QUICK

Chemistry
1 answer:
LenKa [72]3 years ago
5 0
<span>The energy (from food) an organism consumes is mostly burned for the purposes of movement and keeping warm. In terms of the trophic levels, this is energy "wasted" (heat radiated by an animal out to the surrounding environment) and not passed on to the next level as consumable food. For instance, imagine that the sun's rays (the ultimate source of energy in the "food chain") striking a portion of the ocean on the Earth's surface is equal to one million energy units. Much of that energy is absorbed by the ocean's water molecules, but the amount left over is intercepted by phytoplankton and turned into food by photosynthesis. At this first trophic level, the amount of energy the phytoplankton store as food is 20,000 units. At the next trophic level, the zooplankton consume the phytoplankton, but just 2,000 units of energy is passed on as food in the bodies of the tiny animals. Small fish (at the next trophic level) scoop up the little zooplankton, but their bodies only represent 10% of the previous level's energy units - therefore, the amount of energy left is now 200 units. By the time large fish at their trophic level eat the smaller fish, 20 energy units remain. Finally, at the point where humans (at the final trophic level) catch these fish, only 1 or 2 energy units are left. As this example shows, the approximate efficiency at which energy is transferred through the "food chain" from one level to the next highlights the great amount of energy lost in an ecosystem, and how a relatively small amount of energy is actually available to an organism in the form of food that it needs to survive and perpetuate.</span>
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60.0 g of NH Cl are dissolved in 100 grams of water at 60.0° C. This solution is
Sidana [21]

Answer:

B) is the correct answer

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3 years ago
Which statement describes an Arrhenius acid? A. It is a proton donor. B. It is a proton acceptor. C. It produces hydroxide ions
Katen [24]
Hello.

The answer is: D it produces hyrogen ions in a solution.

This is correct because when Arrhenius acid it turns into hydrogen ions.substance as an acid if it produces hydrogen ions H(+) or hydronium ions in water. A substance is classified as a base if it produces hydroxide ions OH(-) in water.

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3 0
3 years ago
Read 2 more answers
The pungency of chillies is due to ____________.​
Vera_Pavlovna [14]

Answer:

The hotness or pungency of chilli is due to presence of a group of compounds called capsaicinoids. Among capsaicinoids, capsaicin and dihydrocapsaicin are present in major quantities, while homocapsaicin, nordihydrocapsaicin and homo-dihydrocapsaicin are present in very small quantities.

3 0
2 years ago
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If you start with 6 moles of N2 and 6 moles of H2 (meaning you won't have enough of 1 of the ingredients), how many moles of NH3
Ivahew [28]

Answer:

4molNH_3

Explanation:

Hello there!

In this case, according to the given information it will be firstly necessary to set up the chemical equation taking place:

N_2+3H_3\rightarrow 2NH_3

We infer we need to calculate the moles of NH3 by using both of the moles of N2 and H2 at the beginning, in order to identify the limiting reactant:

n_{NH_3}=6molN_2*\frac{2molNH_3}{1molN_2}=12molNH_3\\\\ n_{NH_3}=6molH_2*\frac{2molNH_3}{3molH_2}=4molNH_3\\

Thus, since hydrogen yields the fewest moles of ammonia, we conclude that we are just able to yield 4 moles of NH3.

Regards!

8 0
3 years ago
A sample of sodium-24 with an activity of 14 mCi is used to study the rate of blood flow in the circulatory system. If sodium-24
SOVA2 [1]

Answer:

See explanation

Explanation:

From;

0.693/t1/2 = 2.303/t log (Ao/A)

Where;

t1/2 = half life of the sodium-24

t = time taken

Ao = initial activity of sodium-24

A= activity of sodium-24 at time t

a)

0.693/15 = 2.303/15 log (14/A)

0.0462 = 0.1535 log (14/A)

0.0462/0.1535 =  log (14/A)

log (14/A) = 0.0462/0.1535

14/A = Antilog(0.3)

14/A= 1.995

A = 14/1.995

A = 7.0 mCi

b)

0.693/15 = 2.303/30 log (14/A)

0.0462 =0.0768 log(14/A)

0.0462/0.0768 =log (14/A)

(14/A) =Antilog (0.6)

A = 14/Antilog (0.6)

A = 3.5 mCi

c)

0.693/15 = 2.303/45 log (14/A)

0.0462= 0.0512 log (14/A)

log (14/A) = 0.0462/0.0512

log (14/A) = 0.9

(14/A) = Antilog (0.9)

A= 14/Antilog (0.9)

A = 14/7.9

A = 1.77  mCi

d)

2.5 days = 2.5 * 24 hours = 60 hours

0.693/15 = 2.303/60 log (14/A)

0.0462 = 0.03838 log (14/A)

log (14/A) = 0.0462/0.03838

(14/A) = Antilog(1.2)

A= 14/Antilog(1.2)

A = 14/15.8

A = 0.886 mCi

Note that activity (A) decreases as time increases.

5 0
3 years ago
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