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Trava [24]
3 years ago
10

What is the molar mass of an unknown gas if the density of that gas is 0.726 grams/liter at a pressure of 0.634 atm and a temper

ature of 25oC?
a. 2.35 g/mole
b. 28.0 g/mole
c. 53.2 g/mole
d. 64.0 g/mole
Chemistry
1 answer:
pshichka [43]3 years ago
5 0

Answer:

b. 28.0 g/mole

Explanation:

Given:

d = 0.726 g/L

P = 0.634 atm

T = 25°C + 273 = 298 K

We can use the ideal gas equation of state:

PV= nRT

Since d=mass/V = nM/V, we can modify the equation to obtain the molar mass of the gas (M):

PM = dRT

⇒ M = dRT/P = (0.726 g/L x 0.082 L.atm/K.mol x 298 K)/(0.634 atm)= 27.87 g/mol ≅ 28 g/mol

Therefore, the correct option is b. 28.0 g/mole

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Hey there!:

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* therefore Cl gains electrons .

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* in MnCl2 the oxidation state of Mn is +2

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The teacher said the volume of the liquid was 500 mL when measured a student found it was 499.7 mL what is the students percent
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Answer:

<h2>0.06 % </h2>

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The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

error = 500 - 499.7 = 0.3

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Hurry please!
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Answer : The mass of of water present in the jar is, 298.79 g

Solution : Given,

Mass of barium nitrate = 27 g

The solubility of barium nitrate at 20^oC is 9.02 gram per 100 ml of water.

As, 9.02 gram of barium nitrate present in 100 ml of water

So, 27 gram of barium nitrate present in \frac{27g}{9.02g}\times 100ml=299.33ml of water

The volume of water is 299.33 ml.

As we know that the density of water at 20^oC is 0.9982 g/ml

Now we have to calculate the mass of water.

\text{Mass of water}=\text{Density of water}\times \text{Volume of water}

\text{Mass of water}=(0.9982g/ml)\times (299.33ml)=298.79g

Therefore, the mass of of water present in the jar is, 298.79 g

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