Answer:
H3PO4 Mol mass..
= (3 x H1 = 3) + (1 x P31 = 31) + (4 x O16 = 64). = 98g/mol.
a)..Hydrogen: = 3 / 98 = 0.0306 x 100% = 3.06%.
b)..Phosphorus = 31/98 = 0.3162 x 100% = 31.63%.
c)..Oxygen = 64/98 = 0.6531 x 100% = 65.31%.
(Total = 100% H3PO4).
Explanation:
Find the molar mass of all the elements in the compound in grams per mole.
Find the molecular mass of the entire compound.
Divide the component's molar mass by the entire molecular mass.
You will now have a number between 0 and 1. Multiply it by 100% to get percent composition.
What would happen to the amount of matter on earth if mass were not conserved during changes of state?
Answer : The balanced chemical equation is,
The coefficient for 
is, 4 and on reactant side of the equation 
is present.
Explanation :
Rules for the balanced chemical equation in basic solution are :
- First we have to write into the two half-reactions.
- Now balance the main atoms in the reaction.
- Now balance the hydrogen and oxygen atoms on both the sides of the reaction.
- If the oxygen atoms are not balanced on both the sides then adding water molecules at that side where the more number of oxygen are present.
- If the hydrogen atoms are not balanced on both the sides then adding hydroxide ion
at that side where the less number of hydrogen are present. - Now balance the charge.
The half reactions in the basic solution are :
Reduction : 
......(1)
Oxidation : 
.....(2)
Now multiply the equation (1) by 2 and then added both equation, we get the balanced redox reaction.
The balanced chemical equation in a basic solution will be,
Thus, the coefficient for is, 4 and on reactant side of the equation is present.
Explanation:
Heat energy lost by metal = Heat energy gained by water.
(0.00138kg) * c * (99.6-31.6) = (0.006050kg) * 4.148 * (31.6-22.1)
c = 2.541J/kg°C
Answer:
E) 3.0x10⁻¹²
Explanation:
Ksp of Cu(OH)₂ is defined as:
Cu(OH)₂(s) ⇄ Cu²⁺(aq) + 2 OH⁻(aq)
Ksp = [Cu²⁺] [OH⁻]²
When pH is 10.1, [OH⁻] is:
pOH = 14 - pH
pOH = 3.9
pOH = -log [OH⁻]
<em>[OH⁻] = 1.26x10⁻⁴M</em>
<em />
Replacing in ksp formula:
4.8x10⁻²⁰= [Cu²⁺] [1.26x10⁻⁴]²
<em>3.0x10⁻¹² = [Cu²⁺] </em>
That means the maximum amount of Cu²⁺ that can be in solution is 3.0x10⁻¹²M, thus, molar solubility of Cu(OH)₂ is
<em>E) 3.0x10⁻¹²</em>
