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2 years ago

Which interactions and processes contribute to the dissolution of ionic compounds in water?

Chemistry

1 answer:

artcher [175]2 years ago

6 0

Answer:

Ion-dipole attraction and solvation of the ions

Step-by-step explanation:

Assume you have an ionic compound MX.

Ion-dipole interactions:

Water is a highly polar molecule.

The partially negative O atom is strongly attracted to the M⁺ cations at the surface of the solid. The partially positive H atoms are strongly attracted to the X⁻ ions.

If the water molecules hit the surface of the solid with the right orientation, the ion-dipole attractions will help dislodge the ions from the surface.

Solvation:

Once the ions are in solution, the ions are stabilized by solvation. The strong ion-dipole attractions cause a shell of water ions to form around the ionss.

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Ronch [10]

Answer:

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2 years ago

Which of the following has no electrical charge?

Shtirlitz [24]

Answer:

neutron

Explanation

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2 years ago

A balloon has a volume of 6.2 liters at 23.2 C. The balloon is then heated to a temperature of 144.0 C. What is the volume of th

Marina CMI [18]

Answer:

8.7 L

Explanation:

T2(V1/T1) = V2

417.15 K(6.2 L/296.45 K) = 8.7 L

Remember to almost always change celcius to kelvin. Also, this is part of Charle's Law (temp and volume are proportional, so if temp increaces so must the volume or vice versa). Lastly, Charle's Law has the formula of V1/T1 = V2/T2. I just rearranged it to go along with your problem. Hence, the T2(V1/T1) = V2

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3 years ago

How many milliliters of .085 m naoh are required to titrate 25 ml of .072 m hbr to the equivalence point?

SOVA2 [1]

The ML of 0.85 m NaOH required to titrate 25 ml of 0.72m hbr to the equivalence point is calculated as follows

calculate the moles of HBr used

moles = molarity x volume

25 x0.072/1000= 0.0018 moles

write the equation for reaction

NaOH + HBr = NaBr + H2O
from reacting equation the mole ratio between NaOH to HBr is 1:1 therefore the moles of NaOH = 0.0018 moles

volume = moles/molarity
0.0018/0.085 = 0.021 L in Ml = 0.021 x1000=21.18 Ml ofNaOH

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2 years ago

The painkiller, Advil® contains the active ingredient ibuprofen (IB), which has a pKb of

denis23 [38]

This problem is providing the basic dissociation constant of ibuprofen (IB) as 5.20, its pH as 8.20 and is requiring the equilibrium concentration of the aforementioned drug by giving the chemical equation at equilibrium it takes place. The obtained result turned out to be D) 4.0 × 10−7 M, according to the following work:

First of all, we set up an equilibrium expression for the given chemical equation at equilibrium, in which water is omitted for it is liquid and just aqueous species are allowed to be included:

$Kb=\frac{[IBH^+][OH^-]}{[IB]}$

Next, we calculate the concentration of hydroxide ions and the Kb due to the fact that both the pH and pKb were given:

$pOH=14-8.20=5.80$

$[OH^-]=10^{-5.8}=1.585x10^{-6}M$

$Kb=10^{-5.20}=6.31x10^{-6}$

Then, since the concentration of these ions equal that of the conjugated acid of the ibuprofen (IBH⁺), we can plug in these and the Kb to obtain:

$6.31x10^{-6}=\frac{(1.585x10^{-6})(1.585x10^{-6})}{[IB]}$

Finally, we solve for the equilibrium concentration of ibuprofen:

$[IB]=\frac{(1.585x10^{-6})(1.585x10^{-6})}{6.31x10^{-6}}=4.0x10^{-7}$

Learn more:

(Weak base equilibrium calculation) brainly.com/question/9426156

4 0

2 years ago