Answer:15
Step-by-step explanation:
Given
Craftsman sell 10 Jewelry set for $500 each
For each additional set he will decrease the price by $ 25
Suppose he sells n set over 10 set
Earning![=\text{Price of each set}\times \text{no of set}](https://tex.z-dn.net/?f=%3D%5Ctext%7BPrice%20of%20each%20set%7D%5Ctimes%20%5Ctext%7Bno%20of%20set%7D)
Earning ![=(500-25n)(10+n)](https://tex.z-dn.net/?f=%3D%28500-25n%29%2810%2Bn%29)
![E=5000+500n-25n^2-250n](https://tex.z-dn.net/?f=E%3D5000%2B500n-25n%5E2-250n)
differentiate to get the maximum value
![\frac{dE}{dn}=-50n+250](https://tex.z-dn.net/?f=%5Cfrac%7BdE%7D%7Bdn%7D%3D-50n%2B250)
Equate
to get maximum value
![-50n+250=0](https://tex.z-dn.net/?f=-50n%2B250%3D0)
![n=\frac{250}{50}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B250%7D%7B50%7D)
![n=5](https://tex.z-dn.net/?f=n%3D5)
Thus must sell 5 extra set to maximize its earnings.
Answer:
Step-by-step explanation:
3*n*p*6 = 18np
The cuic equation is -1 and 2i
<h3>
Answer: 19 dimes</h3>
=================================================
Work Shown:
d = number of dimes
q = 32-d = number of quarters
$5.15 = 515 cents
10d+25q = 515
10d+25(32-d) = 515
10d+800-25d = 515
-15d+800 = 515
-15d = 515-800
-15d = -285
d = -285/(-15)
d = 19
There are 19 dimes. You can stop here if you want.
q = 32-d = 32-19 = 13
There are 13 quarters
-------------------------------
Check:
1 dime = 10 cents
19 dimes = 19*10 = 190 cents
1 quarter = 25 cents
13 quarters = 13*25 = 325 cents
total value = 190 cents + 325 cents = 515 cents = $5.15
The answer is confirmed.
Answer:
Order Data (least to greatest): 35,40,42,46,47,52
Mean: 43.66
MAD:4.66
Could not figure out Mean of Differences sorry!
Step-by-step explanation:
To find the mean you add all of the numbers and divide by the amount.
To find MAD find the sum of the data values, and divide the sum by the number of data values.