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2 years ago

-0.5(14a - 22) = ? this for my work, please help me.

Mathematics

1 answer:

stealth61 [152]2 years ago

8 0

Answer:

-7a+11

Step-by-step explanation:

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The function f(x) = 1.25x^2 models the packaging costs, in cents, for a box shaped like a rectangular prism. The side lengths ar

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I need this tooo, did u find it??

Step-by-step explanation:

5 0

3 years ago

Please help me with this it might look easy to you but not to me :

Rasek [7]

Answer:

Step-by-step explanation:

5/6 =0.8333

12x0.8333 = 10

7 0

3 years ago

Solve the problem give the equation using x as the variable and give the answer. If 1 is subtracted from a number and this diffe

V125BC [204]

Answer:

x=6

Step-by-step explanation:

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3(x-1)=15+x

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6 0

3 years ago

Discrete R.V. Assume a student shows up for EGR 280 completely unprepared and the instructor gives a pop quiz. Assume there are

Tom [10]

Answer:

a) p=0.2

b) probability of passing is 0.01696

c) The expected value of correct questions is 1.2

Step-by-step explanation:

a) Since each question has 5 options, all of them equally likely, and only one correct answer, then the probability of having a correct answer is 1/5 = 0.2.

b) Let X be the number of correct answers. We will model this situation by considering X as a binomial random variable with a success probability of p=0.2 and having n=6 samples. We have the following for k=0,1,2,3,4,5,6

$P(X=k) = \binom{n}{k}p^{k}(1-p)^{n-k} = \binom{6}{k}0.2^{k}(0.8)^{6-k}$ .

Recall that $\binom{n}{k}= \frac{n!}{k!(n-k)!}$ In this case, the student passes if X is at least four correct questions, then

$P(X\geq 4) = P(X=4)+P(X=5)+P(X=6)=\binom{6}{4}0.2^{4}(0.8)^{6-4}+\binom{6}{5}0.2^{5}(0.8)^{6-5}+\binom{6}{6}0.2^{6}(0.8)^{6-6}= 0.01696$

c)The expected value of a binomial random variable with parameters n and p is $E[X] = np$ . IN our case, n=6 and p =0.2. Then the expected value of correct answers is $6\cdot 0.2 = 1.2$

5 0

3 years ago

The employees of a firm that manufactures insulation are being tested for indications of asbestos in their lungs. The firm is re

diamong [38]

Answer:

0.070

Step-by-step explanation:

Y = number on trial

Y has a negative binomial distribution

r = 3

P = 30% = 0.3 probability of positive indication.

P(Y = 11) probability of 11 employees that must be tested to get 3 positives

Y-1Cr-1*p^r*q^(y-r)

Y-1 = 11-1 = 10

r-1 = 3 -1 = 2

10C2 x 0.3³x0.7⁸

45x0.027x0.05764801

= 0.070

This is the probability that 11 employees must be tested to get 3 positives.

8 0

2 years ago