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3 years ago

Match the equivalent expressions.

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

7 0

Answer:

see below

Step-by-step explanation:

5(x + y) + 6(x − y)

Distribute

5x+ 5y + 6x -6y

Combine like terms

11x -y

(5x − 3y) − x + 3x − 5y

Combine like terms

5x -x +3x -3y -5y

7x -8y

4(x + y) − 3(x + y)

Distribute

4x +4y -3x -3y

Combine like terms

x -y

x − 4x + 6y + (14x − 5y)

Combine like terms

x -4x +14x +6y -5y

11x +y

3x + 3y + 2(2x − y)

Distribute

3x+3y +4x -2y

Combine like terms

7x +y

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A high school principal wishes to estimate how well his students are doing in math. Using 40 randomly chosen tests, he finds tha

ollegr [7]

Answer:

99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Step-by-step explanation:

We are given that a high school principal wishes to estimate how well his students are doing in math.

Using 40 randomly chosen tests, he finds that 77% of them received a passing grade.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of students received a passing grade = 77%

n = sample of tests = 40

p = population proportion

<em>Here for constructing 99% confidence interval we have used One-sample z proportion test statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5%

level of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

<u>99% confidence interval for p</u> = [ $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.77-2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ , $0.77+2.5758 \times {\sqrt{\frac{0.77(1-0.77)}{40} } }$ ]

= [0.5986 , 0.9414]

Therefore, 99% confidence interval for the population proportion of passing test scores is [0.5986 , 0.9414].

Lower bound of interval = 0.5986

Upper bound of interval = 0.9414

6 0

2 years ago

Which three lengths could be the lengths of the sides of a triangle? A.21 cm, 7 cm, 7 cm B.9 cm, 14 cm, 22 cm C.15 cm, 5 cm, 20

lapo4ka [179]

B.) 9 cm, 14 cm, 22 cm

It would make an obtuse triangle, and by using the triangle calculator trick or ways you would have to find the area of the triangle, but it would get to confusing...

But also the simplest way or elementary would be

A.) 21 cm, 7 cm 7 cm

I messed up my self I'm am truly sorry but,

I hoped this helped!! <33

5 0

3 years ago

The Fahrenheit and Celsius scales are related by the equation F=9/5C+32. What temperature is equal to a body temperature of 98.6

____ [38]

$\textbf{Substitute\ in\ the\ equation}$