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12345 [234]
3 years ago
15

Please help me answer the question in the picture!

Mathematics
1 answer:
Natasha2012 [34]3 years ago
7 0

Answer:

x=75

Step-by-step explanation:

A( I mean angle)+B+C+D=360°

A=C

B=D

2A+2D=360°

A+D=180°

30°+x+x=180°

2x=150°

x=75

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Can someone help pls
Travka [436]

Answer: V = 706.5 cubic millimeters

Step-by-step explanation:

V = (3.14)(r^2)(h)

V = (3.14)(5^2)(9)

V = (3.14)(25)(9)

V = 706.5

5 0
3 years ago
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A spinner is divided into four equal sections. Which situation can be represented using this simulation?
Travka [436]

Answer: A

Step-by-step explanation: Because its a 25% chance to pick a color of rose, its also a 25% chance to land a certain color with the spinner.

8 0
2 years ago
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The sum of 2 consecutive numbers is 37. Find the numbers.
lisov135 [29]
The sum of 2 consecutive numbers is 37. Find the numbers.

If x represents the smaller integer, then the larger integer is <span>x+1.</span>
5 0
3 years ago
Help asap ------------------------------
Grace [21]

Answer:

(0,-41)

Step-by-step explanation:

Let see if this table of values are proportional.

  • All x values decrease by -9.
  • All y values decrease by -19.

This mean that the function is proportional. This also gives us the slope which is 19/9.

This tell us that this function will be a linear function since we are trying to find the y intercept we would use this equation

We know the slope and we know a point so let use point slope form to find the intercept.

y - y  _1= m(x - x _1)

Let use points (-18,-79) and let m =19/9.

y + 79 =  \frac{19}{9} (x + 18)

y + 79 =  \frac{19}{9} x + 38

y =  \frac{19}{9} x   - 41

This is in slope intercept form so the y intercept is

- 41

The answer is -41.

6 0
3 years ago
Sec^6x(secxtanx)-sec^4(secxtanx)=sec^5xtan^3x<br> Verify the trigonometric identity
mario62 [17]

I guess you mean

\sec^6x(\sec x\tan x)-\sec^4x(\sec x\tan x)=\sec^5x\tan^3x

On the left side, we have a common factor of \sec^4x(\sec x\tan x)=\sec^5x\tan x, so that

\sec^6x(\sec x\tan x)-\sec^4x(\sec x\tan x)=\sec^5x\tan x(\sec^2x-1)

Recall that

\sec^2x=1+\tan^2x

from which it follows that

\sec^5x\tan x(\sec^2x-1)=\sec^5x\tan x\tan^2x=\sec^5x\tan^3x

7 0
3 years ago
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