X=27 and y=11
if you let each number equal x and y we know the sum is 38 so x+y=38
and the smaller is 16 less than the larger
. so if we say the smaller number is 7 then x-16=y
these can be solved as a simultaneous equation. x+(x-16)=38
2x-16=38
2x=54
x=27
(27)-16=y
y=11
so the answer is x=27 y=11
Answer:
Y < 3x+2
Step-by-step explanation:
Answer: y = 3/2x + 1
Step-by-step explanation: For a perpendicular line, take the reciprocal of "m" and reverse the sign.
- 2/3 becomes +3/2
Then substitute the y and x values of the given coordinate into the equation and solve for "b"
y = mx + b
-2 = 3/2(-2) + b
-2 = -3 + b
-2 +3 = b
+1 = b Substitute for b in y = (3/2)x + 1
I did 54/8 because you are multiplying D×8 and the product of 54/8= 6.75 so yeah the answer is 6.75