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andreev551 [17]
4 years ago
6

Find the kinetic energy K of a satellite with mass m in a circular orbit with radius R. Express your answer in terms of m, M, G,

and R.
Physics
1 answer:
ratelena [41]4 years ago
3 0

Answer:

K=\frac{GmM}{2R}

Explanation:

The kinetic energy is defined as:

K=\frac{mv^2}{2}(1)

Here, m is the object's mass and v its speed. In this case the speed of the satellite is the orbital speed, which is given by:

v_{orb}=\sqrt\frac{GM}{R}(2)

Here, G is the gravitational constant, M is the mass of the object that the satellite is orbiting and R is the radius of its circular orbit. Replacing (2) in (1):

K=\frac{mv_{orb}^2}{2}\\K=\frac{m(\sqrt\frac{GM}{R})^2}{2}\\K=\frac{GmM}{2R}

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Answer:

Force, F = 187.42 N

Explanation:

It is given that,

Mass of boy, m = 30 kg

Acceleration due to gravity, a=9.8\ m/s^2

Radius of curvature of the roller coaster, r = 15 m

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The force acting on the boy are force of gravity and the centripetal force. The net force acting on him is as follows :

F=mg-\dfrac{mv^2}{r}

F=m(g-\dfrac{v^2}{r})

F=30\times (9.8-\dfrac{(7.3)^2}{15})

F = 187.42 N

So, he press against the seat with a force is 187.42 N. Hence, this is the required solution.

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