Suppose a rocket launches with an acceleration of 34.0 m/s2 what is the apparent weight of an 85-kg astronaut aboard this rocket
2 answers:
Answer:
the apparent weight of the astronaut in the rocket is 3723 N.
Given:
acceleration = 34
mass of astronaut = 85 kg
To find:
Apparent weight of the astronaut = ?
Solution:
Total weight of the astronaut in a rocket is given by,
W = w + F
W = apparent weight of the astronaut
w = weight of astronaut on earth surface = mg
F = force acting on the astronaut = ma
W = mg+ma
W = m (g+a)
W = 85 (9.8 + 34)
W = 3723 N
Thus, the apparent weight of the astronaut in the rocket is 3723 N.
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Answer:
Explanation:
For a linear elastic material Young's modulus is a constant that is given by:
Here, F is the force exerted on an object under tensio, A is the area of the cross-section perpendicular to the applied force, is the amount by which the length of the object changes and
is the original length of the object. In this case the force is the weight of the mass:
Replacing the given values in Young's modulus formula:
Answer:
293k
Explanation:
In this question, we are asked to calculate the temperature to which the reaction must be heated to double the equilibrium constant.
To find this value, we will need to use the Van’t Hoff equation.
Please check attachment for complete solution
Answer:
The impulse on the object is 60Ns.
Explanation:
Impulse is defined as the product of the force applied on an object and the time at which it acts. It is also the change in the momentum of a body.
F = m a
F = m()
⇒ Ft = m( -
)
where: F is the dorce on the object, t is the time at which it acts, m is the mass of the object, is its initialvelocity and
is the final velocity of the object.
Therefore,
impulse = Ft = m( -
)
From the question, m = 3kg, = 0m/s and
= 20m/s.
So that,
Impulse = 3 (20 - 0)
= 3(20)
= 60Ns
The impulse on the object is 60Ns.