we are given in the problem the following dimensions or specifications
B = 0.000055 T r = 0.25 m constant mu0 = 4*pi*10-7
The formula that is applicable from physics is
B = mu0*I/(2*pi*r) I = 2*B*pi*r/mu0 I = 68.75 Amperes
Capillary action<span> occurs when the adhesion to the walls is stronger than the cohesive</span>forces<span> between the liquid molecules. The </span>height to which capillary action will take water<span> in a uniform circular </span>tube<span> (picture to left) is limited by surface tension and, of course, gravity.
Hope this helps. :)</span>
vf=vi+at
8.77=vi+1.77 x 3.33
8.77 = vi+5.8941
vi=2.8759
vf²=vi²+2ad
8.77²=2.8759²+2x 1.77 x d
76.9129=8.27 + 3.54d
d=19.39 m
