Please HELPPPPPP!!!!!!!!

Out of 132 seventh graders 33 voted math as their favorite subject. What percentage is this?

snow_lady [41]

Answer:

25%

Step-by-step explanation:

To find the percentage, we take the amount that found math as their favorite subject and divide it by the total amount of students.

33/132 = .25

This is in decimal form. To change it to percent form, multiply by 100

.25 * 100 = 25 percent

6 0

3 years ago

Read 2 more answers

Find the 120th term of the following sequence <br> 7, 14, 21, ...<br> a120 =

dlinn [17]

Answer:

840

Step-by-step explanation:

There is a common difference d between consecutive terms, that is

d = 14 - 7 = 21 - 14 = 7

This indicates the sequence is arithmetic with n th term

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 7 and d = 7 , thus

$a_{120}$ = 7 + (119 × 7 ) = 7 + 833 = 840

4 0

3 years ago

A tobacco company claims that the amount of nicotene in its cigarettes is a random variable with mean 2.2 and standard deviation

Aleksandr-060686 [28]

Answer:

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$

In this problem, we have that:

$\mu = 2.2, \sigma = 0.3, n = 100, s = \frac{0.3}{\sqrt{100}} = 0.03$

What is the approximate probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true?

This is 1 subtracted by the pvalue of Z when X = 3.1. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{3.1 - 2.2}{0.03}$

$Z = 30$

$Z = 30$ has a pvalue of 1.

1 - 1 = 0

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

4 0

4 years ago

Can someone please answer this?

rosijanka [135]

Answer:

13 foot rounded to the nearest foot

Step-by-step explanation:

the ratio is

nose to head: 2:9

Rushmore mountain Roosevelt :

nose to head : x/60

2/9=x/60

120=9x

x=120/9= 13 1/3 or 13.33

x=13 foot rounded to the nearest foot

3 0

3 years ago

PLS HELP WILL GIVE BRAINLIAST !!!

DENIUS [597]

Answer:

32.5 feet long and 20 feet wide

Step-by-step explanation:

To solve for the length first, you have it measured as 26 in long and each 4 in is 5 ft so you can go ahead and divide 26 in by 4 in and that gives you 6.5 in so what we did was figure out how many 4 in were in 26 in and therefore we have a 6.5 and so just to match that to the 5 ft per each 4 in (in this case we have 6.5) so we multiply 6.5*5 and that equals 32.5 ft which is the length of the garden bed.

Next we are going to solve for the width which is 16 in wide in the scale and so again each 4 in is 5 ft so here again we're going to divide 16 in by 4 in and that equals 4 in and so again each 4 in is 5 ft so we're going to go ahead and multiply 4 * 5 and that gets you 20 ft which is the width of the garden bed.

8 0

3 years ago