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Lady_Fox [76]
2 years ago
6

Find the missing vertical angles.​

Mathematics
1 answer:
never [62]2 years ago
3 0

Answer:

L1 = 113°

L4 = 67°

Step-by-step explanation:

L1 + L2 = 180°

L1 = 180° - L2

L1 = 180° - 67°

L1 = 113°

L3 + L4 = 180°

L4 = 180° - L3

L4 = 180° - 113°

L4 = 67°

Proof-

Combination of L1,L2,L3 and L4 should be 360°

113°+67°+113°+67° = 360°

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I have been stuck on this forever plz help <br> What is the surface area of this cylinder
Andrei [34K]

Answer:

1865.16 m^2

Step-by-step explanation:

first let 's find radius of a circle

radius=diameter/2

=18/2

=9 m

area of a cylinder=2πrh+2πr2

=2*3.14*9*24 + 2*3.14*(9)^2

=1356.48 + 2*3.14*81

=1356.48 + 508.68

=1865.16 m^2

6 0
3 years ago
Read 2 more answers
Find the distance between the points A (13, 2) and B (7, 10).
Aliun [14]

Answer:

10

Step-by-step explanation:

d = 10

For:

(X1, Y1) = (13, 2)

(X2, Y2) = (7, 10)

Distance Equation Solution:

d=(7−13)2+(10−2)2−−−−−−−−−−−−−−−−−√

d=(−6)2+(8)2−−−−−−−−−−√

d=36+64−−−−−−√

d=1–√00

d=10

4 0
3 years ago
Card
Burka [1]

Answer:

19,27 cm^2

Step-by-step explanation:

area of triangle = (6 x 3)/ 2 = 9 cm^2

circle area : 3^2 x 3,14 = 28,27 cm^2

area of shaped region = 28,27 - 9 = 19,27 cm^2

6 0
3 years ago
7m+9, for m=2.<br> What's the value of this equation
Vinil7 [7]

Answer:

replace m with 2 and do 7(2)+9

5 0
3 years ago
Duck #1 lays eggs whose weights are normally distributed with a mean of 70gramsand a standard deviation of 6 grams.Duck #2 lays
Genrish500 [490]

Answer:

26.11% probability that Duck #2’s egg weighs more than Duck #1’s egg

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If an egg is randomly chosen from each duck, what is the probability that Duck #2’s egg weighs more than Duck #1’s egg?

Duck #2 egg will weigh more if the subtraction of duck's 2 egg by duck's 1 egg is larger than 0.

When we subtract normal distributions, the mean is the subtraction of the means. So

\mu = 65 - 70 = -5

The standard deviation is the square root of the sum of the variances. So

\sigma = \sqrt{6^2+5^2} = \sqrt{61} = 7.81

Now, we have to find 1 subtracted by the pvalue of Z when X = 0. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0 - (-5)}{7.81}

Z = 0.64

Z = 0.64 has a pvalue of 0.7389

1 - 0.7389 = 0.2611

26.11% probability that Duck #2’s egg weighs more than Duck #1’s egg

4 0
3 years ago
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