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REY [17]
3 years ago
12

It's sunny in New York, but it is cool. Where would you expect to find this lizard during the day? Question 16 options: Under a

rock In a damp stream bed Basking in a sunny spot In a hole in the ground.
Chemistry
1 answer:
cupoosta [38]3 years ago
7 0

It's sunny in new york, but it is cool, we will expect to find lizard under a rock or in a hole in the ground, where temperature is more than outside.

<h3>Why lizards are not comfortable in cold?</h3>

Lizards are not easily survive in the winter season as they are cold blooded animal, so their body will not active in the winter season.

During the winter season or in the cold weather, lizards will go to the places where they feel less cooling. And these places be like inside the rocks, under a hole, under the ground, in the trunks of trees, etc. due to high temperature.

Hence, options (1) and (4) are correct.

To know more about lizards, visit the below link:

brainly.com/question/407800

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lisov135 [29]
The correct answer that would best complete the given statement above is option B. Heat in a substance is an example of a kinetic energy. Kinetic energy is a kind of energy that is in motion. We can feel the kinetic energy of heat through their temperatures because heat is being transferred. 
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Answer:

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Explanation:

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4 years ago
Oh, no! You just spilled 85.00 mL of 1.500 M sulfuric acid on your lab bench and need to clean it up immediately! Right next to
vredina [299]

Explanation:

We will balance equation which describes the reaction between sulfuric acid and sodium bicarbonate: as follows.

   H_2SO_4(aq) + 2NaHCO_3(s) \rightarrow Na2SO_4(aq) + 2H_2O(l) + 2CO_2(g)

Next we will calculate how many moles of H_2SO_4 are present in 85.00 mL of 1.500 M sulfuric acid.

As,       Molarity = \frac{\text{moles of solute}}{\text{liters of solution&#10;}}

            1.500 M = \frac{n}{0.08500 L&#10;}

                    n = 0.1275 mol H_2SO_4

Now set up and solve a stoichiometric conversion from moles of H_2SO_4  to grams of NaHCO_3. As, the molar mass of NaHCO_3 is 84.01 g/mol.

 0.1275 mol H_2SO_4 \times (\frac{2 mol NaHCO_3}{1 mol H_2SO_4}) \times (\frac{84.01 g NaHCO_3}{1 mol NaHCO_3})

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So unfortunately, 15.00 grams of sodium bicarbonate will "not" be sufficient to completely neutralize the acid. You would need an additional 6.42 grams to complete the task.

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3 years ago
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