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zhannawk [14.2K]
3 years ago
6

H2(g) + F2(g) → 2 HF(g) ΔH=-546 kJ

Chemistry
2 answers:
Ulleksa [173]3 years ago
5 0

Answer: The answer is D, More energy was released in the formation of the 2 HF bonds than in the breaking of the bonds of H2 and F2.

Explanation: Honestly, I guessed on this question and got it right, but I see that right after the arrow on the right side of the equation, there's a 2 in front of the HF(g). On the left side of the equation, it does not match the right side, which led me to believe that there was more energy being released.

Arisa [49]3 years ago
4 0

Answer: help please !!

Explanation:

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ΔG° = ∑np . ΔG°f(p) - ∑nr . ΔG°f(r)

where,

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ΔG°f(): standard Gibbs free energy of formation

p: products

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ΔG° = 3 mol × ΔG°f(Mg²⁺(aq)) + 2 mol × ΔG°f(Al(s)) - 3 mol × ΔG°f(Mg(s)) - 2 mol × ΔG°f(Al³⁺(aq))

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