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olga55 [171]
3 years ago
6

What is the slope-intercept form of 11x-13y=39?

Mathematics
1 answer:
Inessa05 [86]3 years ago
4 0

Answer:

Step-by-step explanation:

y=11/13x−3

hope this helps and mark me brainliest as well please.

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The length of the base of an isosceles triangle is x. The length of a leg is 4x - 6. The perimeter of the triangle is 51. Find x
harkovskaia [24]

Answer:

Step-by-step explanation:

if the base=x

length of one leg is =4x-6

length of the other leg is also =4x-6 (isosceles)

P=x+4x-6+4x-6=51

9x-12=51

9x=51+12

9x=63

x=63/9=7

x=7

6 0
3 years ago
How do i solve 562.34-64.89 and show my work
grandymaker [24]
Best to write this problem as shown below:

<span>562.34
 -64.89
-----------     First, estimate the correct answer.  It would be 562-65 = 497.


Must borrow from the tenths column, because 9 is greater than 4.  We end up with 5 under the 4 and 9.  We must borrow again to obtain the next digit:

12-8=4, so the result is now .45

11-4=7, so the result is now 7.45

55-6=9, so the result is now 97.45.

Finally, 4-0=4, so the final result is 497.45.  Compare this to the estimate (497).

Here we've had to borrow 4 times.</span>
4 0
4 years ago
Read 2 more answers
Use the equation below to answer the question.
JulijaS [17]

Answer:

The signa notation to represent the first five ten f(x) is given by f(x)=\sum\limits^{5}_{n=1}a_n

Step-by-step explanation:

Given sequence is -5, -9, 13...

Let f(x) be the given sequence and is denoted by

f(x)=\{-5,-9,-13,...\}

Let the first term be a_1, 2^{\textrm{nd}}  term be a_3,...

ie, a_1=-5,a_2=-9, a_3=-13,...

To find the common difference d:

d=a_2-a_1

=-9-(-5)

=-9-(+5)

d=-4

d=a_3-a_2

=-13-(-9)

=-13+9

d=-4

Therefore the common difference d is -4 for given sequence f(x) with a_1=-5 and d=-4, the seqence f(x) is an arithmetic sequence

By defintion of arithmetic sequence

a_n=a+(n-1)d\hfill(1)

Now to find a_4, a_5:

put n=4 in equation (1)

a_4=a+(4-1)d

a_4=-5+(3)(-4)        [since a=-5, d=-4]

=-5-12

a_4=-17

in equation (1)

a_5=a+(5-1)d

a_5=-5+(4)(-4)       [since a=-5, d=-4]

=-5-16

a_5=-21

Therefore a_4=-17 and a_5=-21

Therefore f(x)=\{-5,-9,-13,-17,-21,...\}

Now to represent the sum of the first five terms of f(x) using sigma notation as below

f(x)=\sum_{n=1}^5 a_n

where \sum_{n=1}^5 a_n=a_1+a_2+a_3+a_4+a_5

           -5-9-13-17-21

\sum_{n=1}^5 a_n=-65

4 0
4 years ago
Find the area of a circle with a circumference of 31.4 units
erma4kov [3.2K]

Answer:

Step-by-step explanation:

hope it helps you

4 0
3 years ago
Simplify. Assume that no denominator is equal to zero. (2a/a^2) ^-3
Gnesinka [82]

Answer:

I'm pretty sure its either A or C

Step-by-step explanation:

5 0
3 years ago
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