Answer:
$11,983
Step-by-step explanation:
YEAR;Amount
0 $5,000
1 $5,300
2 $5,618
3 $5,955
4 $6,312
5 $6,691
6 $7,093
7 $7,518
8 $7,969
9 $8,447
10 $8,954
11 $9,491
12 $10,061
13 $10,665
14 $11,305
15 $11,983
<em>They took 101 peaches to market.</em>
<u>Check:</u>
In the 1st hour, they sold (101/2 + 1/2) = 102/2 = 51. They had 50 left.
In the 2nd hour, they sold (50/3 + 1/3)=51/3=17. They had (50-17)=33 left.
In the 3rd hour, they sold (33/4 + 3/4) = 36/4 = 9. They had (33-9) = 24 left.
In the final hour, they sold (24/5 + 1/5) = 25/5 = 5. They had (24-5) = 19 left. yay!
Fiona and Camilla took their 19 remaining peaches and went home. Sharing with
their parents and their brother Rowlf, each person had 3.8 peaches for dinner.
There was a lot of activity in the bathroom overnight.
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The key to solving this one is to work it backwards.
-- They had 19 peaches left at the end of the day.
-- During the final hour, the 1/5 of a peach that they sold left them with 19,
so they had 19-1/5 before they sold the 1/5 of a peach.
The 19-1/5 was 4/5 of what they had at the beginning of the final hour.
So, at the beginning of the final hour, they had (5/4)x(19.2) = 24 .
-- During the 3rd hour, the 3/4 of a peach that they sold left them with 24,
so they had 24-3/4 before they sold the 3/4 of a peach.
The 24-3/4 was 3/4 of what they had at the beginning of that hour.
So, at the beginning of the 3rd hour, they had (4/3)x(24.75) = 33 .
Do the same for the 2nd hour.
Then do the same for the 1st hour.
And you'll work your way back up to 101 peaches.
Answer:
15 kg
Step-by-step explanation:
Radius of a solid sphere : mass of a solid sphere
3 cm : 9 kg
Find the mass of a sphere of the same material of radius 5 cm
Radius of a solid sphere : mass of a solid sphere
5 cm : x kg
Equate both ratios to find x
3 cm : 9 kg = 5 cm : x kg
3/9 = 5/x
3 * x = 9 * 5
3x = 45
x = 45/3
x = 15 kg
The mass of a sphere of the same material of radius 5 cm is 15 kg
What do you mean? whats the question?
Here I copy the steps and indicate where the error is.
Square root of negative 2x plus 1 − 3 = x=> <span>this is the starting equation
</span>
√[ - 2x + 1] - 3 = x
Square root of negative 2x plus 1 − 3 + 3 = x + 3 in this step she added 3 to each side, which is fine
<span> Square root
of negative 2x plus 1 = x + 3 <span>she made the addtions => fine</span></span>
Square root of negative 2x plus 1 − 1 = x + 3 – 1 due to <span>plus 1 in inside the square root, this step will not help</span>
<span> Square root
of negative 2 x = x + 2 <span>wrong! she cannot simplify - 1 that is out of the square root with +1 that is inside the square root
</span></span>
<span>Then, from here on all is wrong, but she made other additional mistakes.</span>
(Square root of negative 2 x)2 = (x − 4)2 −2x <span> the right side should be (x+2)^2 which is x^2 + 4x +4 not (x-4)^2 - 2x</span>
Later she made a mistake changing the sign of -8x to +8x
Those are the mistakes. Finally, the global error is that she should verify whether the found values satisfied the original equation.
