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KatRina [158]
3 years ago
8

Factor x^4+2x^3−2x−1 completely

Mathematics
1 answer:
goblinko [34]3 years ago
5 0
1) Factor out common terms in the first two terms, then in the last two terms
{x}^{3}(x+2)-2(x+2)

2) Factor out the common term x+2
(x+2)({x}^{3}-2)

Done!
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Given m parallel to I, and m2 7 = 94, find the measure of angle 5
mote1985 [20]

Answer:

97

Step-by-step explanation:

3 0
3 years ago
Mathematics, Help, not sure about my answer on this one
olga nikolaevna [1]

Answer:

F. 2 1/9

Step-by-step explanation:

Step 1: Substitute q

r = 3(\frac{1}{3^n} )+2

When you plug in <em>n</em> = 1, 2, 3:

n(1) = 3

n(2) = 2.11111

n(3) = 2.3333

So our answer is F.

3 0
2 years ago
A rectangular window is topped with a semicircle the height of the rectangle part is 1 more than 3 times its width W meters whic
devlian [24]

Answer:

A = 3W² + W + 1/8πW²

Step-by-step explanation:

rectangular window is L x W

semicircle is 1/2 πr²

r = 1/2 W

L = 3W + 1

A = W(3W + 1) + 1/2 π(1/2W)²

A = 3W² + W + 1/8πW²

4 0
3 years ago
Read 2 more answers
I need help on this one
cupoosta [38]
593-540=53
9 R8
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3 0
2 years ago
37% dextrose solution (37 mg per 100ml of solution) is given iv. Suppose a total of 3.81 liters is given over a 15 hour period.
sashaice [31]

Answer:

During 15 hour period, 1409.7 mg of dextrose will be delivered.

The flow rate of dextrose per hour will be 93.98 mg/hour.

Step-by-step explanation:

If a total of 3.81 liters of the solution is given over a 15 hour period.

Now, 1 liter is equivalent to 1000 ml

So, a total of 3810 ml of the solution is given over a 15 hour period.

If 100 ml of solution contains 37 mg of dextrose, then 3810 ml of the solution will contain \frac{37 \times 3810}{100} = 1409.7 mg of dextrose.

So, during the 15 hour period, 1409.7 mg of dextrose will be delivered.

The flow rate of dextrose per hour will be \frac{1409.7}{15} = 93.98 mg/hour. (Answer)

7 0
3 years ago
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