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2 years ago

HELP MEEE , need the right answer

Mathematics

2 answers:

qwelly [4]2 years ago

7 0

Answer: A. c = nv

Step-by-step explanation: This is simple algebra, despite the complicated variables involved. Just think of it as a normal equation.

First, we multiply both sides by v to get rid of c/v. Thus, nv = c. We can switch sides since c also equals nv. So, the answer of c = nv, or A in the multiple choice.

Ksenya-84 [330]2 years ago

3 0

Answer:

Step-by-step explanation:

We do the opposite.

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The distance between Taylor’s house and her school is 300,000 centimeters.

Sergio [31]

Answer:

30 km

Step-by-step explanation:

1 kilometer = 100 meters.

1 meter = 100 cm

therefore, 1 km = 10,000

and then, 300000 cm is 30 km

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3 years ago

When given Three points on a coordinate plane, you may be able to find a specific Quadratic equation that intersects all given p

ohaa [14]

Answer:

TRUE

Step-by-step explanation:

A quadratic equation can be found that will go through any three distinct points that ...

satisfy the requirements for a function
are not on the same line

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The key word here is "may." You will not be able to find a quadratic intersecting the three points if they do not meet both requirements above.

8 0

3 years ago

If a university wants to maintain a 14:1 ratio between students and teachers, how many teachers would be needed to accommodate 8

zheka24 [161]

<span>So we want to know the number of teachers the university should have if the ratio of students to teachers is 14:1 and the number of students is 896. If x is the number of teachers: 14/1=896/x. Now we solve for x: Lets multiply both sides with x: x*(14/1)=896 and divide both sides by 14 and we get: x=896/14 and x=64. So the university should have 64 teachers.</span>

7 0

3 years ago

Read 2 more answers

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago

How many cups in a gallon of milk

KatRina [158]

Using the metric system, a gallon is equal to 16 cups.
Therefore, there are 16 cups in a gallon of milk.

I hope this helps a lot! :)

6 0

3 years ago