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stiv31 [10]
2 years ago
6

Bob did a survey asking adults which pet they wished they had as a kid. The results are below. If 720 adults said the pet they w

ished they had was a dog, how many adults wished they had a rabbit?

Mathematics
1 answer:
nata0808 [166]2 years ago
7 0

Answer: there iis none so cose zero

Step-by-step explanation:

Bob did a survey asking adults which pet they wished they had as a kid. The results are below. If 720 adults said the pet they wished they had was a dog, how many adults wished they had a rabbit?

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I can not figure out how to do this question and I need help please
spayn [35]
\bf \textit{quadratic formula}\\\\

\begin{array}{lcclll}
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a&b&c
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\qquad \qquad 
x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}
6 0
3 years ago
Adam plans to choose a video game from a section of the store where everything is 75% off. He writes the expression d−0.75d to f
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is 0.75d becase the missing numbers should be the same number

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1. A trandle with a penmeter of 36 inches Is dilated with a scale factor of 2. What will be
Strike441 [17]

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3 years ago
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How do you write 9/2 as a percentage?
olga55 [171]
9/2 would be converted to 450%
6 0
3 years ago
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The curves y = √x and y=(2-x) and the Cartesian axes form two distinct regions in the first quadrant. Find the volumes of rotati
makkiz [27]

Answer:

Step-by-step explanation:

If you graph there would be two different regions. The first one would be

y = \sqrt{x} \,\,\,\,, 0\leq x \leq 1 \\

And the second one would be

y = 2-x \,\,\,\,\,,  1 \leq x \leq 2.

If you rotate the first region around the "y" axis you get that

{\displaystyle A_1 = 2\pi \int\limits_{0}^{1} x\sqrt{x} dx = \frac{4\pi}{5} = 2.51 }

And if you rotate the second region around the "y" axis you get that

{\displaystyle A_2 = 2\pi \int\limits_{1}^{2} x(2-x) dx = \frac{4\pi}{3} = 4.188 }

And the sum would be  2.51+4.188 = 6.698

If you revolve just the outer curve you get

If you rotate the first  region around the x axis you get that

{\displaystyle A_1 =\pi \int\limits_{0}^{1} ( \sqrt{x})^2 dx = \frac{\pi}{2} = 1.5708 }

And if you rotate the second region around the x axis you get that

{\displaystyle A_2 = \pi \int\limits_{1}^{2} (2-x)^2 dx = \frac{\pi}{3} = 1.0472 }

And the sum would be 1.5708+1.0472 = 2.618

7 0
3 years ago
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