<span>33% of 21=6.93 i think this is the answer</span>
Since A (3,4) A’(9,12)
You can see 3*3=9
Therefor it was enlarged by 3times
Scale factor of 3
Answer:
9 and 6
Step-by-step explanation:
Write down the system.
The two numbers are x and y.
We are therefore given:
x+y=15
x-y=3
I will solve this for elimination since it is already setup for it.
I will add the columns since both equations are in the same form.
2x+0y=18
2x =18
Divide both sides by 2:
x =18/2
Simplify:
x =9
So if x+y=15 and x=9, then y=6.
The two numbers are 9 and 6.
Test:
9+6=15
9-6=3
Answer:
Step-by-step explanation:
a) -14 , -9 , -4 , 1 ................
Common difference = d = 2nd term - 1st term
= -9-[-14]
= -9 + 14
d = 5
The next term can be got by adding 5 to the previous term
5th term = 1 + 5 = 6
6th term = 6 + 5 = 11
7th term = 11 + 5 = 16
Next 3 terms are : 6 , 11 , 16
9. x + (y - 3 - 4x + 2( 3x - (-y - 1) + 2y) - 3x)
= x + (y - 3 - 4x + 2 (3x + y - 1) + 2y - 3x)
= x + (y - 3 - 4x + 6x + 2y - 2 + 2y - 3x)
= (x - 4x + 6x - 3x) + (y + 2y + 2y) - (3+2)
= 0 + 5y - 5
= 5y - 5 (or simplified as 5(y-1)
10. 6 + (-a -3(b + 6(a - b)+4a) - 2b)
= 6 + (-a - 3(b + 6a - 6b + 4a) -2b)
= 6 + (-a - 3b + 18a - 18b + 12a - 2b)
= 6 + (-a + 18a + 12a) + (-3b - 18b - 2b)
= 6 + 29a - 23b
Lmk if it's wrong, I'll try to edit it.
