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Pachacha [2.7K]
2 years ago
14

A retail store stocks two types of shirts A and B. These are packed in attractive cardboard boxes. During a week the store can s

ell a maximum of 400 shirts of type A and a maximum of 300 shirts of type B. The storage capacity, however, is limited to a maximum of 600 both types combined. Type A shirt fetches a profit of $2 per unit and type B a profit of $5 per unit. How many of each type the store should stock per week to maximize the total profit? (Use the graphic method)
Computers and Technology
1 answer:
antiseptic1488 [7]2 years ago
7 0
300 of A and 300 of b
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Answer:

(a)\ 222_{10} = DE_{16} --- True

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To do this, we convert DE from base 16 to base 10 using product rule.

So, we have:

DE_{16} = D * 16^1 + E * 16^0

In hexadecimal.

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So, we have:

DE_{16} = 13 * 16^1 + 14 * 16^0

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First, convert D7 to base 10 using product rule

D7_{16} = D * 16^1 + 7 * 16^0

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So, we have:

D7_{16} = 13 * 16^1 + 7 * 16^0

D7_{16} = 215_{10}

Next convert 215 to base 2, using division rule

215 / 2 = 107 R 1

107/2 =53 R 1

53/2 =26 R1

26/2 = 13 R 0

13/2 = 6 R 1

6/2 = 3 R 0

3/2 = 1 R 1

1/2 = 0 R1

Write the remainders from bottom to top.

D7_{16} = 11010111_2

<em>Hence (b) is false</em>

(c)\ 13_{16} = 19_{10}

Convert 13 to base 10 using product rule

13_{16} = 1 * 16^1 + 3 * 16^0

13_{16} = 19

Hence; (c) is true

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