How do you multiply 0.205 x 0.234?

In a triangle, the middle length side is 3 more than the shortest side, and the longest side is double the middle length side. T

Tamiku [17]

Let's call the short side "s"
short side = "s"
middle side = 3s
longest side = 2*3*s
perimeter = 45 cm
perimeter = s + 3s + 6s = 45
short side = 4.5
middle = 13.5
long side = 27

4.5 + 13.5 + 27 = 45

8 0

3 years ago

(1/2a - 2/3b) ( 3/5a + 2/3b) multiply the following

11111nata11111 [884]

Answer:

Step-by-step explanation:

$(\dfrac{1}{2}a-\dfrac{2}{3}b)(\dfrac{3}{5}a+\dfrac{2}{3}b)=\dfrac{1}{2}a*(\dfrac{3}{5}a+\dfrac{2}{3}b) - \dfrac{2}{3}b*(\dfrac{3}{5}a+\dfrac{2}{3}b) \\\\\\= \dfrac{1}{2}a*\dfrac{3}{5}a + (\dfrac{1}{2}a*\dfrac{2}{3}b) - \dfrac{2}{3}b*\dfrac{3}{5}a- \dfrac{2}{3}b*\dfrac{2}{3}b\\\\\\=\dfrac{3}{10}a^{2} + \dfrac{1}{3}ab - \dfrac{2}{5}ab -\dfrac{4}{9}b^{2}\\\\=\dfrac{3}{10}a^{2} +\dfrac{1*5}{3*5}ab-\dfrac{2*3}{5*3}-\dfrac{4}{9}b^{2}\\\\\\$

$=\dfrac{3}{10}a^{2}+\dfrac{5}{15}ab-\dfrac{6}{15}ab -\dfrac{4}{9}b^{2}\\\\=\dfrac{3}{10}a^{2}-\dfrac{1}{15}-\dfrac{4}{9}b^{2}$

8 0

3 years ago

Solve 5(2^x+4)=15 round to the nearest thousandth

Novosadov [1.4K]

Answer:

Step-by-step explanation:

Begin by dividing by 5

2x + 4 = 3

Is this written as 2^(x + 4) = 3? I think it is.

Take the log of both sides

log 2^(x + 4) = log(3)

(x + 4) * log(2) = log 3

log 2 = 0.30103

log 3 = 0.47712

(x + 4) = log2 / log3

x + 4 = 0.63093 Add 4 to both sides

x = -3.369 Rounded to the nearest thousandth

====================

If you mean the question exactly as it is written (the 4 is not part of the power)

5(2^x + 4) = 15

2^x + 4 = 3

2^x = 3 - 4

2^x = - 1

This can't be done 2 to any power should be >0.

if x>0 then this will give an ever increasing number

if xK0 then this will give an ever decreasing answer but still greater than 0.

No value will make 2^x go to something minus.

If I have misread this in some way, leave a note and I will get back to you.

5 0

3 years ago

2. Given a quadrilateral with vertices (−1, 3), (1, 5), (5, 1), and (3,−1):

zlopas [31]

<h2>Explanation:</h2>

In every rectangle, the two diagonals have the same length. If a quadrilateral's diagonals have the same length, that doesn't mean it has to be a rectangle, but if a parallelogram's diagonals have the same length, then it's definitely a rectangle.

So first of all, let's prove this is a parallelogram. The basic definition of a parallelogram is that it is a quadrilateral where both pairs of opposite sides are parallel.

So let's name the vertices as:

$A(-1,3) \\ \\ B(1,5) \\ \\ C(5,1) \\ \\ D(3,-1)$

First pair of opposite sides:

<u>Slope:</u>

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

Second pair of opposite sides:

<u>Slope:</u>

$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$

So the diagonals measure the same, therefore this is a rectangle.

5 0

4 years ago

Rosa has 55 books and gives 5 of them to her friend. How many does she have left?

Alecsey [184]

Answer:

55-5

50 books she has left

7 0

3 years ago