Answer:
![\sqrt[5]{2^4}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7B2%5E4%7D)
Step-by-step explanation:
Maybe you want 2^(4/5) in radical form.
The denominator of the fractional power is the index of the root. Either the inside or the outside can be raised to the power of the numerator.
![2^{\frac{4}{5}}=\boxed{\sqrt[5]{2^4}=(\sqrt[5]{2})^4}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B4%7D%7B5%7D%7D%3D%5Cboxed%7B%5Csqrt%5B5%5D%7B2%5E4%7D%3D%28%5Csqrt%5B5%5D%7B2%7D%29%5E4%7D)
__
In many cases, it is preferred to keep the power inside the radical symbol.
<span>if
1c<span>m3</span>=1mm</span>
then<span><span>
1942×1c<span>m3</span>=1942×1mm</span></span>
1) 108
2) 72
3) 36
4) 72
5) 72
6) 144
7) 72
8) 72
9) 108
10) 108
I hope this helped
Yes, -0.5 is an integer because it is a negative number. Any number that is positive or negative is an integer.
Answer:
x = no solutions
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
Step-by-step explanation:
<u>Step 1: Define equation</u>
4x - 5 = x - 1 + 3x
<u>Step 2: Solve for </u><em><u>x</u></em>
- Combine like terms: 4x - 5 = 4x - 1
- Subtract 4x on both sides: -5 ≠ -1
Here we see that -5 does not equal -1.
∴ This equation has no solutions.
