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const2013 [10]
2 years ago
11

Find the missing side length of the right triangle below 6 inches 12 inches

Mathematics
1 answer:
jek_recluse [69]2 years ago
8 0
The missing length of the right triangle should be 6 inches
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9,6,3,0,-3,-6 work out the nth term (it decrease by the same amount each time)
Shkiper50 [21]

Answer:

-3n+11 or 3n+11 or 3n-11 one of those

Step-by-step explanation:

8 0
3 years ago
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Fraction 4 over 5 n = Fraction 2 over 3. n = ___?
Taya2010 [7]

Answer:

Step-by-step explanation:

(4/5)n = (2/3)

move 4/5 to the right

n = (2/3)/(4/5)

n = 5/6

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3 years ago
Given that R=9x+8y find x when y=8 and R=4
Ilya [14]

Answer:

Step-by-step explanation:

R = 9x + 8y

4 = 9x + 8*8

4 = 9x + 64

Subtract 64 from both sides

4 - 64 = 9x + 64 - 64

-60 = 9x

Divide both sides by 9

-60/9 = 9x/9

-20/3 = x

x = -6 2/3

8 0
3 years ago
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Anna had $54 in her purse. She bought a book for $26.34 and a book marker for $1.27. Anna’s mom then gave her $10 for completing
jekas [21]

Answer:

Anna has $36.39 dollars.

Step-by-step explanation:

All we have to do is subtract

54 - (26.34 + 1.27) =

54 - 27.61 =

36.39

So, the answer is 36.39

Hope this helps! :)

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2 years ago
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Estimate the following quantities without using a calculator. Then find a more precise result, using a calculator if necessary.
zubka84 [21]

Explanation:

a. It is so easy to double a number that no approximation is necessary.

  31,000 × 200 = 3.1×10⁴ × 2×10² = 6.2×10⁶ exactly

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b. 6.2×10³ × 5.2×10⁶ ≈ 6×5×10⁹ = 3×10¹⁰ approximately

The approximation can be refined a bit by taking the ".2" into account:

  6.2×10³ × 5.2×10⁶ ≈ (6×5 + .2×(6+5))×10⁹

  = 32.2×10⁹ = 3.22×10¹⁰ approximately

Actual product: 3.224×10¹⁰.

For most purposes, the approximation is an adequate approximation, as it it within 10% of the actual value.

__

c. 9×10⁶ -2.3×10⁴ ≈ 9×10⁶ approximately

A better approximation is to actually subtract an approximation of the smaller number:

  9×10⁶ -2.3×10⁴ ≈ (9 - 0.02)×10⁶ ≈ 8.98×10⁶ approximately

The actual value uses all of the digits of the smaller number:

  9×10⁶ -2.3×10⁴ ≈ (9 - 0.023)×10⁶ = 8.977×10⁶ exactly

As in part B, either approximation is adequate for most purposes, as the difference from the actual value is less than .3%.

_____

The accuracy required of an approximation, hence the work you expend improving accuracy, should depend on the need in the final application of the number. Often, approximations are used for budget or resource planning purposes where some "slop" is allowed or even expected.

They can also be used in engineering applications, where the error needs to be on the side of more safety (rather than less).

7 0
3 years ago
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