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Sav [38]
4 years ago
11

(3x + 8) - (3x - 9) in standard form

Mathematics
2 answers:
DanielleElmas [232]4 years ago
8 0
If in standard form you mean slope intercept form, then you are looking to create an equation that looks like this:

y = mx + b

So you need to move around the numbers whilst keeping both sides equivalent.

3x - 9 = 7y
7y = 3x - 9
y = (3x)/7 - 9/7

Your answer should look like this:

y = (3x)/7 - 9/7

lord [1]4 years ago
7 0
The answer would be 17.

3x + 8 - 3x + 9

(3x - 3x) + 8 + 9

8 + 9

17.
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Which of the following is equal to the expression (8x)^-2/3 (27x)¯1/3
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The equivalent expression of (8x)^-2/3 * (27x)^-1/3 is 1/12x

<h3>How to evaluate the expression?</h3>

The expression is given as:

(8x)^-2/3 * (27x)^-1/3

Evaluate the exponent 8^-2/3

(8x)^-2/3 * (27x)^-1/3 = 1/4(x)^-2/3 * (27x)^-1/3

Evaluate the exponent (27x)^-1/3

(8x)^-2/3 * (27x)^-1/3 = 1/4(x)^-2/3 * 1/3(x)^-1/3

Multiply 1/4 and 1/3

(8x)^-2/3 * (27x)^-1/3 = 1/12(x)^-2/3 * (x)^-1/3

Evaluate the exponent

(8x)^-2/3 * (27x)^-1/3 = 1/12(x)^(-2/3 -1/3)

This gives

(8x)^-2/3 * (27x)^-1/3 = 1/12(x)^(-1)

So, we have

(8x)^-2/3 * (27x)^-1/3 = 1/12x

Hence, the equivalent expression of (8x)^-2/3 * (27x)^-1/3 is 1/12x

Read more about equivalent expression at

brainly.com/question/2972832

#SPJ1

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